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  • How to write update query using some {$variable} with example

    如何使用一些{$variable}编写更新查询,例如:

    $query="update subjects set values username='{$name}', hash_password='{$pass}' where id=1";
    

    You cannot use values there, it should be:

    $query="update subjects set username='{$name}', hash_password='{$pass}' where id=1";
    

    But I would recommend using a prepared statement instead of dumping variables straight into your query.


    Create a PDO connection:

    // Usage:   $db = connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword);
    // Pre:     $dbHost is the database hostname, 
    //          $dbName is the name of the database itself,
    //          $dbUsername is the username to access the database,
    //          $dbPassword is the password for the user of the database.
    // Post:    $db is an PDO connection to the database, based on the input parameters.
    function connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword)
    {
       try
        {
            return new PDO("mysql:host=$dbHost;dbname=$dbName;charset=UTF-8", $dbUsername, $dbPassword);
        }
        catch(PDOException $PDOexception)
        {
            exit("<p>An error ocurred: Can't connect to database. </p><p>More preciesly: ". $PDOexception->getMessage(). "</p>");
        }
    }
    

    Init it like this:

    $host = 'localhost';
    $user = 'root';
    $databaseName = 'databaseName';
    $pass = '';
    

    And call it like this:

    $db = connectToDatabase($host, $databaseName, $user, $pass);
    

    And use a function like this:

    function update($db, $username, $password, $id)
    {
        $query = "UPDATE subjects SET username = :username, hash_password = :password WHERE id = :id;";
        $statement = $db->prepare($query); // Prepare the query.
        $result = $statement->execute(array(
            ':username' => $username,
            ':password' => $password,
            ':id' => $id
        ));
        if($result)
        {
            return true;
        }
        return false
    }
    

    Now finally, you can do something like:

    $username = "john";
    $password = "aefasdfasdfasrfe";
    $id = 1;
    
    $success = update($db, $username, $password, $id);
    

    You also avoid sql injection by doing it like this (preparing the statements, and executing the variables into the statement).


    If you don't wanna read up on context/database escaping, this is how you avoid such problems using PDO for example:

    $pdo = new PDO('mysql:host=localhost;dbname=db', 'user', 'pw');
    
    $pdo->prepare("update subjects set values username=?, hash_password=? where id=?")
        ->execute(array($user, $pass, 1)); 
    

    See also:

  • How can I prevent SQL injection in PHP?
  • http://bobby-tables.com/
  • 链接地址: http://www.djcxy.com/p/93696.html

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