String contains in Bash

2018-05-29 06:14:19

I have a string in Bash:

string="My string"

How can I test if it contains another string?

if [ $string ?? 'foo' ]; then
  echo "It's there!"
fi

Where ?? is my unknown operator. Do I use echo and grep ?

if echo "$string" | grep 'foo'; then
  echo "It's there!"
fi

That looks a bit clumsy.

You can use Marcus's answer (* wildcards) outside a case statement, too, if you use double brackets:

string='My long string'
if [[ $string = *"My long"* ]]; then
  echo "It's there!"
fi

Note that spaces in the needle string need to be placed between double quotes, and the * wildcards should be outside.

如果你喜欢正则表达式的方法：

string='My string';

if [[ $string =~ .*My.* ]]
then
   echo "It's there!"
fi

我不确定使用if语句，但是您可以通过case语句获得类似的效果：

case "$string" in 
  *foo*)
    # Do stuff
    ;;
esac

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