在Java问题中蛮力数独求解算法

除了解决方法之外,一切似乎都能在算法中正常工作。 当它使用可解数独板执行程序时,它说它不能解决。 我已经尝试了解决方法中所能想到的一切。 我试过调试,并且在测试第一行后失败。 有什么建议么? 以下是迄今为止的完整代码:

    public class SudokuSolver {

 public static void initializeGrid(int[][] grid, int[][] puzzle) {

  for (int r = 0; r < puzzle.length; r++) {
  for (int c = 0; c < puzzle[0].length; c++) {
  grid [r][c] = puzzle [r][c];
   }
  } 
 }

 public static void displayGrid(int[][] grid) {

  for (int r = 0; r < grid.length; r++) {
   if (r % 3 == 0) {
   System.out.println("+---+---+---+");
   }
   for (int c = 0; c < grid[r].length; c++) {
if (c % 3 == 0) {
 System.out.print("|");
}
displayDigits(r, c, grid);

} System.out.print(“|”); 的System.out.println(); } System.out.println(“+ --- + --- + --- +”); }

if(grid [r] [c] == 0){System.out.print(''); } else {System.out.print(grid [r] [c]); }} public static int getEmptyCells(int [] [] grid,int [] [] emptyCells){int i = 0; int numEmptyCells = 0; for(int r = 0; r <grid.length; r ++){for(int c = 0; c <grid [r] .length; c ++){if(grid [r] [c] == 0){emptyCells [i] [0] = r; emptyCells [i] [1] = c; numEmptyCells ++; 我++; }}} return numEmptyCells; }

private static boolean hasNoDuplicates(int [] digitsList){for(int j = 0; j <digitsList.length; j ++){for(int k = j + 1; k <digitsList.length; k ++){if(digitsList [j ] == digitsList [k] && digitsList [j]!= 0)return false; }}返回true; }

private static boolean checkCurrentRow(int [] [] grid,int currentRow){
int [] digitsList = new int [grid.length]; for(int c = 0; c <digitsList.length; c ++){digitsList [c] = grid [currentRow] [c]; } if(hasNoDuplicates(digitsList)){return true; }返回false; }

private static boolean checkCurrentCol(int [] [] grid,int currentCol){int [] digitsList = new int [grid.length]; for(int i = 0; i <digitsList.length; i ++){digitsList [i] = grid [i] [currentCol]; } if(hasNoDuplicates(digitsList)){return true; }返回false; }

private static boolean checkCurrentRegion(int [] [] grid,int currentRow,int currentCol){
int [] digitsList = new int [grid.length]; currentRow =(currentRow / 3)* 3; currentCol =(currentCol / 3)* 3; int i = 0; for(int r = 0; r <3; r ++){for(int c = 0; c <3; c ++){digitsList [i] = grid [currentRow + r] [currentCol + c]; 我++; }} if(hasNoDuplicates(digitsList)){return true; }返回false; }

public static boolean isConsistent(int [] [] grid,int currentRow,int currentCol){if(checkCurrentRow(grid,currentRow)&& checkCurrentCol(grid,currentCol)&& checkCurrentRegion(grid,currentRow,currentCol)){return true; }返回false; }

public static boolean solvePuzzle(int [] [] grid,int [] [] emptyCells,int numEmptyCells){int i = 0; int j = 0; int currentCellDigit = grid [emptyCells [i] [0]] [emptyCells [i] [1]]; while(j <numEmptyCells){if(currentCellDigit!= 9){currentCellDigit ++; grid [emptyCells [i] [0]] [emptyCells [i] [1]] = currentCellDigit; if(isConsistent(grid,emptyCells [i] [0],emptyCells [i] [1])){grid [emptyCells [i] [0]] [emptyCells [i] [1]] = currentCellDigit; 我++; J ++; } else {grid [emptyCells [i] [0]] [emptyCells [i] [1]] = currentCellDigit - 1; }} else {currentCellDigit = 0; currentCellDigit = grid [emptyCells [i] [0]] [emptyCells [i] [1]]; 一世 - ; j--; if(j <0){return false; }}}

返回true;
}

public static void main(String [] args){

final int SIZE = 9; int [] [] puzzle = {{0,2,9,0,0,3,0,0,5},{5,0,7,0,0,0,0,9,0},{6 ,0,0,0,0,9,4,2,0},{3,0,2,0,0,4,0,0,0},{0,0,5,0,3,0 ,7,0,0},{0,0,0,5,0,0,6,0,2},{0,9,8,4,0,0,0,0,3},{0 ,3,0,0,0,0,1,0,6},{2,0,0,3,0,0,9,4,0}};

int [] [] grid = new int [SIZE] [SIZE]; int [] [] emptyCellsList = new int [SIZE * SIZE] [2]; int numEmptyCells = 0;

initializeGrid(grid,puzzle); numEmptyCells = getEmptyCells(grid,emptyCellsList); System.out.println(“The puzzle:”); displayGrid(难题); 如果(solvePuzzle(grid,emptyCellsList,numEmptyCells)){System.out.println(“has been resolved:”); displayGrid(网格); }其他{System.out.println(“无法解决!”); }}}

你的initializeGrid是错误的。 恕我直言,它应该是:

for (int c = 0; c < puzzle[r].length; c++)

代替

for (int c = 0; c < puzzle[0].length; c++)

编辑:我的答案低于此

它已被正确缩进(第1课)并相应地安排大括号(第2课)。 学习如何逐行理解你正在尝试做什么,以及何时遇到特定的线路或方法调用,寻求帮助(第3课)。 下面的代码将编译,但不会(尚未)解决这个难题。 阅读并替换solvePuzzle中的注释给我(第四课)。 做一些思考和分析,因为这是你的功课;)祝你好运!

public class SudokuSolver {
  public static void initializeGrid(int[][] grid, int[][] puzzle) {
   for (int r = 0; r < puzzle.length; r++) {
     for (int c = 0; c < puzzle[0].length; c++) {
       grid [r][c] = puzzle [r][c];
     }
   } 
  }

  public static void displayDigits(int r, int c, int[][] grid) {
    if (grid[r][c] == 0) {
      System.out.print('0');
    } else {
      System.out.print(grid[r][c]);
    }
  }

  public static void displayGrid(int[][] grid) {
    for (int r = 0; r < grid.length; r++) {
      if (r % 3 == 0) {
        System.out.println("+---+---+---+");
      }
      for (int c = 0; c < grid[r].length; c++) {
        if (c % 3 == 0) {
          System.out.print("|");
        }
      displayDigits(r, c, grid);
      }
      System.out.print("|");
      System.out.println();
    }
    System.out.println("+---+---+---+");
  }

  public static int getEmptyCells(int[][] grid, int[][] emptyCells) {
    int i = 0;
    int numEmptyCells = 0;
    for (int r = 0; r < grid.length; r++) {
       for (int c = 0; c < grid[r].length; c++) {
         if (grid[r][c] == 0) {
           emptyCells[i][0] = r;
           emptyCells[i][1] = c;
           numEmptyCells++;
           i++;
         }
       }
    }
    return numEmptyCells;
  }

  private static boolean hasNoDuplicates(int[] digitsList) {
    for (int j = 0; j < digitsList.length; j++) {
      for (int k = j + 1; k < digitsList.length; k++) {
        if (digitsList[j] == digitsList[k] && digitsList[j] != 0)
          return false;
      }
    }
    return true;
  }

  private static boolean checkCurrentRow(int[][] grid, int currentRow) {
    int[] digitsList = new int[grid.length];
    for (int c = 0; c < digitsList.length; c++) {
      digitsList[c] = grid[currentRow][c];
    }
    if (hasNoDuplicates(digitsList)) {
      return true;
    }
    return false;
  }

  private static boolean checkCurrentCol(int[][] grid, int currentCol) {
    int[] digitsList = new int[grid.length];
    for (int i = 0; i < digitsList.length;  i++) {
      digitsList[i] = grid[i][currentCol];
    }
    if (hasNoDuplicates(digitsList)) {
      return true;
    }
    return false;
  }

  private static boolean checkCurrentRegion(int[][] grid, int currentRow, int currentCol) {
    int[] digitsList = new int[grid.length];
    currentRow = (currentRow / 3) * 3;
    currentCol = (currentCol / 3) * 3;
    int i = 0;
    for (int r = 0; r < 3; r++) {
      for (int c = 0; c < 3; c++) {
        digitsList[i] = grid[currentRow + r][currentCol + c];
        i++;
      }
    }
    if (hasNoDuplicates(digitsList)) {
      return true;
    }
    return false;
  }

  public static boolean isConsistent(int[][] grid, int currentRow, int currentCol) {
    boolean checkRow = checkCurrentRow(grid, currentRow);
    boolean checkCol = checkCurrentCol(grid, currentCol);
    boolean checkReg = checkCurrentRegion(grid, currentRow, currentCol);
    System.out.println("r: " + checkRow + " c: " + checkCol + " r: " + checkReg);
    if (checkRow && checkCol && checkReg) {
      return true;
    }
    return false;
  }

  public static boolean solvePuzzle(int[][] grid, int[][] emptyCells, int numEmptyCells) {
    int i = 0;
    int currentCellDigit = 0;
    while (i < numEmptyCells) {
      if (currentCellDigit != 9) {
        // increment cell value
        currentCellDigit++;
        // assign to current cell the current cell value
        //<var> = currentCellDigit;
        System.out.println("Solving---------------------- :" + currentCellDigit + " R: " + emptyCells[i][0] + " C: " + emptyCells[i][1]);
        // check if value is valid
        if (isConsistent(grid, emptyCells[i][0], emptyCells[i][1])) {
          // reset after setting
          i++;
          currentCellDigit = 0;
        } else {
          // reset cell to zero instead of decrementing it since we're backtracking!
          //grid[emptyCells[i][0]][emptyCells[i][1]] = currentCellDigit - 1;
          //<var> = 0;
        }
      } else {
        // reset current cell to 0
        //<var> = 0;
        // go to previous cell
        i--;
        // exit if theres no cell to backtrack to
        if (i < 0) {
          return false;
        }
        // set previous' cell value as current cell value
        //<var> = grid[emptyCells[i][0]][emptyCells[i][1]];
      }
    }
    return true;
  }

  public static void main(String[] args) {
    final int SIZE = 9;
    int[][] puzzle  = { {0,2,9,0,0,3,0,0,5},
                        {5,0,7,0,0,0,0,9,0},
                        {6,0,0,0,0,9,4,2,0},
                        {3,0,2,0,0,4,0,0,0},
                        {0,0,5,0,3,0,7,0,0},
                        {0,0,0,5,0,0,6,0,2},
                        {0,9,8,4,0,0,0,0,3},
                        {0,3,0,0,0,0,1,0,6},
                        {2,0,0,3,0,0,9,4,0}
                    };

    int[][] grid = new int[SIZE][SIZE];
    int[][] emptyCellsList = new int[SIZE*SIZE][2];
    int numEmptyCells = 0;

    initializeGrid(grid, puzzle);
    numEmptyCells = getEmptyCells(grid, emptyCellsList);
    System.out.println("The puzzle:");  
    displayGrid(puzzle);
    if (solvePuzzle(grid, emptyCellsList, numEmptyCells)) {
      System.out.println("has been solved:");
      displayGrid(grid);
    } else {
      System.out.println("cannot be solved!");
    }
  }
}

PS这将做回溯,如果你已经用正确的代码替换上面的评论。


solvePuzzle考虑你的代码。 gridcurrentCellDigit之间有多个冗余分配。 ij是多余的,他们有相同的价值。

使用调试器来了解你的代码在做什么。

更好的缩进将使您的代码更具可读性。


public static boolean solvePuzzle(int[][] grid, int[][] emptyCells,
        int numEmptyCells) {
    int i = 0;
    int currentCellNum = 0;
    while (i < numEmptyCells) {
        currentCellNum = grid[emptyCells[i][0]][emptyCells[i][1]];
        if (currentCellNum != 9) {
            currentCellNum++;
            grid[emptyCells[i][0]][emptyCells[i][1]] = currentCellNum;
            if (isConsistent(grid, emptyCells[i][0], emptyCells[i][1])) {
                i++;
            } 
        } else {
            currentCellNum = 0;
            grid[emptyCells[i][0]][emptyCells[i][1]] = currentCellNum;
            i--;
            if (i < 0) {
                return false;
            }

        }
    }
    return true;
}
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