Setting a variable in a while loop, in Bash

2018-06-20 08:16:49

This question already has an answer here:

How to set a variable to the output of a command in Bash? 13 answers

You want command substitution:

HASH=$(echo $l | awk '{print$1}')

What you're using is a special syntax for executing programs with pre-set environment variables:

var1=value progname args...

Hence bash is complaining that the value of $l is not a command which could be found.

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