Save output in variable?

2018-06-20 08:08:32

This question already has an answer here:

How to set a variable to the output of a command in Bash? 13 answers

您可以执行以下操作： var1=$(ls -l)

I know three ways to do:

1) Functions are suitable for such tasks:

func (){
ls -l
}

Invoke it by saying func

2) Also another suitable solution could be eval:

var="ls -l"
eval $var

3) The third one is using variables directly:

var=$(ls -l)
OR
var=`ls -l`

you can get output of third solution in good way:

echo "$var"

and also in nasty way:

echo $var

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