Unix shell script find out which directory the script file resides?
基本上我需要使用与脚本文件位置相关的路径运行脚本，如何将当前目录更改为脚本文件所在的同一目录？
在Bash中，你应该得到你需要的这样的东西：
#!/usr/bin/env bash
BASEDIR=$(dirname "$0")
echo "$BASEDIR"
The original post contains the solution (ignore the responses, they don't add anything useful). The interesting work is done by the mentioned unix command readlink with option -f . Works when the script is called by an absolute as well as by a relative path.
For bash, sh, ksh:
#!/bin/bash
# Absolute path to this script, e.g. /home/user/bin/foo.sh
SCRIPT=$(readlink -f "$0")
# Absolute path this script is in, thus /home/user/bin
SCRIPTPATH=$(dirname "$SCRIPT")
echo $SCRIPTPATH
For tcsh, csh:
#!/bin/tcsh
# Absolute path to this script, e.g. /home/user/bin/foo.csh
set SCRIPT=`readlink -f "$0"`
# Absolute path this script is in, thus /home/user/bin
set SCRIPTPATH=`dirname "$SCRIPT"`
echo $SCRIPTPATH
See also: https://stackoverflow.com/a/246128/59087
Assuming you're using bash
#!/bin/bash
current_dir=$(pwd)
script_dir=$(dirname $0)
echo $current_dir
echo $script_dir
This script should print the directory that you're in, and then the directory the script is in. For example, when calling it from / with the script in /home/mez/ , it outputs
/
/home/mez
Remember, when assigning variables from the output of a command, wrap the command in $( and ) - or you won't get the desired output.