为什么我的异常处理程序不会捕获Android SQLite插入错误?
我第一次使用SQLite,并试图学习它的异常处理,所以我在我的测试应用程序中强制插入错误。 发生异常,我看到它写入Eclipse LogCat输出窗口。 但是它不会在代码中被捕获。 我在这里看到了其他一些关于确保使用正确的异常类型的问题,并认为我有这个权利。 任何想法我失踪?
在我的主要活动中的以下语句中, myTable是一个扩展自己的AbstractDbAdapter (具有扩展SQLiteOpenHelper类的DatabaseHelper )的类。
try {
myTable.create("dupkey");
}
catch (android.database.sqlite.SQLiteConstraintException e) {
Log.e(TAG, "SQLiteConstraintException:" + e.getMessage());
}
catch (android.database.sqlite.SQLiteException e) {
Log.e(TAG, "SQLiteException:" + e.getMessage());
}
catch (Exception e) {
Log.e(TAG, "Exception:" + e.getMessage());
}
样本堆栈跟踪:
Error inserting id="dupkey" last_seen_ts=1360624732 first_seen_ts=1360624732 android.database.sqlite.SQLiteConstraintException: error code 19: constraint failed
at android.database.sqlite.SQLiteStatement.native_execute(Native Method)
at android.database.sqlite.SQLiteStatement.execute(SQLiteStatement.java:61)
at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1582)
at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1426)
at com.myCompany.testApp.myTable_DbAdapter.create(myTable_DbAdapter.java:51)
myTable和AbstractDbAdapter类:
public class myTable_DbAdapter extends AbstractDbAdapter {
private static final String DATABASE_TABLE = "myTable";
// column names -- keys for ContentValues()
public static final String KEY_ID = "id";
public static final String KEY_FIRST_SEEN = "first_seen_ts";
public static final String KEY_LAST_SEEN = "last_seen_ts";
public myTable_DbAdapter(Context ctx) {
super(ctx);
}
public long create(String id) {
long firstSeen = System.currentTimeMillis() / 1000; // SQLite timestamps are in seconds
ContentValues args = new ContentValues();
args.put(KEY_ID, id);
args.put(KEY_FIRST_SEEN, firstSeen);
args.put(KEY_LAST_SEEN, firstSeen); // defaults to firstSeen for a new entry
return mDb.insert(DATABASE_TABLE, null, args);
}
}
public abstract class AbstractDbAdapter {
protected static final String TAG = "AbstractDbAdapter";
protected DatabaseHelper mDbHelper = null;
protected SQLiteDatabase mDb = null;
protected static final String TABLE_CREATE_MYTABLE =
"create table myTable (" +
" id text primary key not null" +
", first_seen_ts integer not null" +
", last_seen_ts integer not null" +
");";
protected static final String DATABASE_NAME = "myDB";
protected static final int DATABASE_VERSION = 1;
protected final Context mCtx;
protected static class DatabaseHelper extends SQLiteOpenHelper {
DatabaseHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
// Note: SQLite requires one execSQL per table
db.execSQL(TABLE_CREATE_MYTABLE);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
Log.w(TAG, "Upgrading database from version " + oldVersion + " to " + newVersion + ", which destroys existing data.");
db.execSQL("DROP TABLE IF EXISTS myTable");
onCreate(db);
}
}
public AbstractDbAdapter(Context ctx) {
this.mCtx = ctx;
}
public AbstractDbAdapter open() throws SQLException {
mDbHelper = new DatabaseHelper(mCtx);
mDb = mDbHelper.getWritableDatabase();
return this;
}
public void close() {
if (mDb != null) {
mDb.close();
mDb = null;
}
if (mDbHelper != null) {
mDbHelper.close();
mDbHelper = null;
}
}
}
我在这里找到了答案:SQLiteConstraintException未被捕获
SQLiteDatabase.insert()方法不会引发异常。 D'哦!
对于像我这样的其他SQLite新手来说,如果要在插入数据库时捕获异常,请使用SQLite.insertOrThrow()方法。 它会抛出一个异常,然后你可以捕捉和处理。
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