Retrieve the position (X,Y) of an HTML element

2018-05-29 00:51:30

我想知道如何在JavaScript中获取HTML元素（如img和div的X和Y位置。

The correct approach is to use element.getBoundingClientRect() :

var rect = element.getBoundingClientRect();
console.log(rect.top, rect.right, rect.bottom, rect.left);

Internet Explorer has supported this since as long as you are likely to care about and it was finally standardized in CSSOM Views. All other browsers adopted it a long time ago.

Some browsers also return height and width properties, though this is non-standard. If you're worried about older browser compatibility, check this answer's revisions for an optimised degrading implementation.

The values returned by element.getBoundingClientRect() are relative to the viewport. If you need it relative to another element, simply subtract one rectangle from the other:

var bodyRect = document.body.getBoundingClientRect(),
    elemRect = element.getBoundingClientRect(),
    offset   = elemRect.top - bodyRect.top;

alert('Element is ' + offset + ' vertical pixels from <body>');

The libraries go to some lengths to get accurate offsets for an element.
here's a simple function that does the job in every circumstances that I've tried.

function getOffset( el ) {
    var _x = 0;
    var _y = 0;
    while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
        _x += el.offsetLeft - el.scrollLeft;
        _y += el.offsetTop - el.scrollTop;
        el = el.offsetParent;
    }
    return { top: _y, left: _x };
}
var x = getOffset( document.getElementById('yourElId') ).left;

This worked for me (modified from highest voted answer):

function getOffset(el) {
  el = el.getBoundingClientRect();
  return {
    left: el.left + window.scrollX,
    top: el.top + window.scrollY
  }
}

Using this we can call

getOffset(element).left

getOffset(element).top

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