Bash: Dynamic replacing with perl

2018-06-09 17:49:04

This question already has an answer here:

How do I pass $SHELL variable into a perl search and replace 2 answers

How to concatenate string variables in Bash 27 answers

Remove " + " (spaces and plus). Bash does automatic concatenation for adjacent strings.

echo 'hi!'t"here"  # hi!there

Generating Perl code in this way is only safe because the output of id -g -n $USER won't contain , $ , @ or / .

You were going for

GROUPNAME="$(id -g -n $USER)"
perl -i -pe's/(PLACEHOLDER)/'"$GROUPNAME"'/g' filepath/file

But there's no reason to generate Perl code. That is very error prone. Instead, use one of the following:

export GROUPNAME="$(id -g -n $USER)"
perl -i -pe's/(PLACEHOLDER)/$ENV{GROUPNAME}/g' filepath/file

GROUPNAME="$(id -g -n $USER)" perl -i -pe's/(PLACEHOLDER)/$ENV{GROUPNAME}/g' filepath/file

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