th bit to zero?
This question already has an answer here:
You just have to replace the logical OR with a logical AND operation. You would use the & operator for that:
pt = pt & ~(1 << i);
You have to invert your mask because logical AND ing with a 1 will maintain the bit while 0 will clear it... so you'd need to specify a 0 in the location that you want to clear. Specifically, doing 1 << i will give you a mask that is 000...010..000 where the 1 is in the bit position that you want, and inverting this will give 111...101...111 . Logical AND ing with this will clear the bit that you want.
你可以坚持这一点:
// Set bit at position `bitpos` in `pt` to `bitval`
unsigned char bitpos = 1;
unsigned char pt = 0b01100001;
bool bitval = 1;
// Clear the bit
pt &= ~(1u << bitpos);
// Set the bit
pt |= (bitval << bitpos);
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