Android:窗口管理器:android查看窗口泄露

当我解决我的第一个问题后,这一个出现:(请帮我解决它..

03-02 12:47:02.785 9439-9439 / com.ucu.ccs.classrecord E / WindowManager:android.view.WindowLeaked:Activity com.ucu.ccs.classrecord.Login泄露了窗口com.android.internal.policy。 impl.PhoneWindow $ DecorView {6d17cc4 VE .... R ...... D 0,0-1002,348}这是最初在android.view.ViewRootImpl。(ViewRootImpl.java:465)处添加的。 view.WindowManagerGlobal.addView(WindowManagerGlobal.java:277)at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:69)at android.app.Dialog.show(Dialog.java:312)at com.ucu.ccs.classrecord 。登录android.os.AsyncTask.execute(AsyncTask.java:535)上的android.os.AsyncTask.executeOnExecutor(AsyncTask.java:587),在com.ucu.ccs处登录$ AttemptLogin.onPreExecute(Login.java:158)。 class android.view.View.performClick(View.java:5197)at android.js上的classrecord.Login.isOnline(Login.java:113)在com.ucu.ccs.classrecord.Login $ 1.onClick(Login.java:73)。 view.View android.os.H上的android.os.Handler.handleCallback(Handler.java:739)上的$ PerformClick.run(View.java:20926) 在android.app.ActivityThread.main(ActivityThread.java:5942)处的android.os.Looper.loop(Looper.java:145)处的java.lang.reflect.Method.invoke上的andler.dispatchMessage(Handler.java:95) (Native Method)at com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run(ZygoteInit.java:1399)at com.android.internal.os(java.lang.reflect.Method.invoke(Method.java:372) .ZygoteInit.main(ZygoteInit.java:1194)

这里是我的代码:

buttonLogin.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String instructor_id = editUser.getText().toString().trim();
                String password = editPass.getText().toString().trim();

                SharedPreferences preferences = getSharedPreferences("MyApp", MODE_PRIVATE);
                preferences.edit().putString("password", password).commit();
                preferences.edit().putString("inst_id", instructor_id).commit();

                if (editUser.getText().toString().equals("") || editPass.getText().toString().equals("")){
                    Toast.makeText(getApplicationContext(),"Please enter Instructor ID and Password", Toast.LENGTH_LONG).show();
                }else {
                    isOnline();
                }

            }
        });

public boolean isOnline(){
        ConnectivityManager connectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
        if (networkInfo != null && networkInfo.isConnectedOrConnecting()){
            new AttemptLogin().execute();
        }else {
            checkInternet();
        }
        return false;
    }

class AttemptLogin extends AsyncTask<String, String, String> {
        boolean failure = false;
        String inst_id = editUser.getText().toString();
        String password = editPass.getText().toString();

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            pDialog = new ProgressDialog(Login.this);
            pDialog.setMessage("Attempting login...");
            pDialog.setIndeterminate(false);
            pDialog.setCancelable(true);
            pDialog.show();
        }

        @Override
        protected String doInBackground(String... params) {
            int success;
            try{
                List<NameValuePair> mList = new ArrayList<NameValuePair>();
                mList.add(new BasicNameValuePair("instructor_id", inst_id));
                mList.add(new BasicNameValuePair("password", password));

                Log.d("request!", "starting");

                JSONObject json = jsonParser.makeHttpRequest(LOGIN_URL, "POST", mList);
                Log.d("Login attempt", json.toString());

                success = json.getInt(TAG_SUCCESS);
                if (success == 1) {
                    Log.d("Login Successful!", json.toString());
                    Intent i = new Intent(Login.this, MainActivity.class);
                    startActivity(i);
                    //finish();
                    return json.getString(TAG_MESSAGE);
                }else{
                    Log.d("Login Failure!", json.getString(TAG_MESSAGE));
                    return json.getString(TAG_MESSAGE);
                }

            }catch (JSONException e){
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            session.setLogin(true);
            pDialog.dismiss();
            if (s != null){
                Toast.makeText(getApplicationContext(), s, Toast.LENGTH_SHORT).show();
            }
        }
    }

如果您的活动已被破坏,但您的对话仍在显示,则会发生此错误。 所以你已经在你的activity的onDestroy()中添加了这些代码

@Override
public void onDestroy() {
    super.onDestroy();
    if (dialog != null) {
        dialog.dismiss();
        dialog = null;
    }
}

希望这对你有用。


您在退出某个活动后尝试显示一个对话框。 在您的doInBackground中,当您正在转移您的活动时,在startActivity(i)之前关闭对话框,尝试此操作并让我知道它是否有效。


其实你的活动正在完成一些如何,所以你需要关闭对话框。

在onPause()添加下面的代码

if(isFinishing()){
    if (pDialog!= null) {
        pDialog.dismiss();
        pDialog= null;
    }
}
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