逆小波变换[/ xpost信号处理]
主要问题：如何反转scipy.signal.cwt()函数。
我已经看到Matlab有一个反向连续小波变换函数，它将通过输入小波变换返回数据的原始形式，尽管您可以过滤掉不需要的切片。
MATALAB逆cwt funciton
由于scipy似乎没有相同的功能，我一直在试图弄清楚如何以相同的形式获取数据，同时消除噪音和背景。 我该怎么做呢？ 我试着将它平方去除负值，但是这给了我值得的方式来大而不正确。
这是我一直在尝试的：
# Compute the wavelet transform
widths = range(1,11)
cwtmatr = signal.cwt(xy['y'], signal.ricker, widths)
# Maybe we multiple by the original data? and square?
WT_to_original_data = (xy['y'] * cwtmatr)**2
这里是一个完全可编译的简短脚本，向您展示我想要获取的数据类型以及我拥有的内容：
import numpy as np
from scipy import signal
import matplotlib.pyplot as plt
# Make some random data with peaks and noise
def make_peaks(x):
bkg_peaks = np.array(np.zeros(len(x)))
desired_peaks = np.array(np.zeros(len(x)))
# Make peaks which contain the data desired
# (Mid range/frequency peaks)
for i in range(0,10):
center = x[-1] * np.random.random() - x[0]
amp = 60 * np.random.random() + 10
width = 10 * np.random.random() + 5
desired_peaks += amp * np.e**(-(x-center)**2/(2*width**2))
# Also make background peaks (not desired)
for i in range(0,3):
center = x[-1] * np.random.random() - x[0]
amp = 40 * np.random.random() + 10
width = 100 * np.random.random() + 100
bkg_peaks += amp * np.e**(-(x-center)**2/(2*width**2))
return bkg_peaks, desired_peaks
x = np.array(range(0, 1000))
bkg_peaks, desired_peaks = make_peaks(x)
y_noise = np.random.normal(loc=30, scale=10, size=len(x))
y = bkg_peaks + desired_peaks + y_noise
xy = np.array( zip(x,y), dtype=[('x',float), ('y',float)])
# Compute the wavelet transform
# I can't figure out what the width is or does?
widths = range(1,11)
# Ricker is 2nd derivative of Gaussian
# (*close* to what *most* of the features are in my data)
# (They're actually Lorentzians and Breit-Wigner-Fano lines)
cwtmatr = signal.cwt(xy['y'], signal.ricker, widths)
# Maybe we multiple by the original data? and square?
WT = (xy['y'] * cwtmatr)**2
# plot the data and results
fig = plt.figure()
ax_raw_data = fig.add_subplot(4,3,1)
ax = {}
for i in range(0, 11):
ax[i] = fig.add_subplot(4,3, i+2)
ax_desired_transformed_data = fig.add_subplot(4,3,12)
ax_raw_data.plot(xy['x'], xy['y'], 'g-')
for i in range(0,10):
ax[i].plot(xy['x'], WT[i])
ax_desired_transformed_data.plot(xy['x'], desired_peaks, 'k-')
fig.tight_layout()
plt.show()
此脚本将输出此图像：
在第一个图是原始数据的地方，中间的图是小波变换，最后一个图是我想要作为处理过的（背景和噪声去除）数据得出的。
有没有人有什么建议？ 十分感谢你的帮助。
我最终找到了一个提供了一个名为mlpy的逆小波变换函数的mlpy 。 该函数是mlpy.wavelet.uwt 。 这是我编写的可编辑脚本，如果他们试图去噪声或删除背景，可能会引起人们的兴趣。
import numpy as np
from scipy import signal
import matplotlib.pyplot as plt
import mlpy.wavelet as wave
# Make some random data with peaks and noise
############################################################
def gen_data():
def make_peaks(x):
bkg_peaks = np.array(np.zeros(len(x)))
desired_peaks = np.array(np.zeros(len(x)))
# Make peaks which contain the data desired
# (Mid range/frequency peaks)
for i in range(0,10):
center = x[-1] * np.random.random() - x[0]
amp = 100 * np.random.random() + 10
width = 10 * np.random.random() + 5
desired_peaks += amp * np.e**(-(x-center)**2/(2*width**2))
# Also make background peaks (not desired)
for i in range(0,3):
center = x[-1] * np.random.random() - x[0]
amp = 80 * np.random.random() + 10
width = 100 * np.random.random() + 100
bkg_peaks += amp * np.e**(-(x-center)**2/(2*width**2))
return bkg_peaks, desired_peaks
# make x axis
x = np.array(range(0, 1000))
bkg_peaks, desired_peaks = make_peaks(x)
avg_noise_level = 30
std_dev_noise = 10
size = len(x)
scattering_noise_amp = 100
scat_center = 100
scat_width = 15
scat_std_dev_noise = 100
y_scattering_noise = np.random.normal(scattering_noise_amp, scat_std_dev_noise, size) * np.e**(-(x-scat_center)**2/(2*scat_width**2))
y_noise = np.random.normal(avg_noise_level, std_dev_noise, size) + y_scattering_noise
y = bkg_peaks + desired_peaks + y_noise
xy = np.array( zip(x,y), dtype=[('x',float), ('y',float)])
return xy
# Random data Generated
#############################################################
xy = gen_data()
# Make 2**n amount of data
new_y, bool_y = wave.pad(xy['y'])
orig_mask = np.where(bool_y==True)
# wavelet transform parameters
levels = 8
wf = 'h'
k = 2
# Remove Noise first
# Wave transform
wt = wave.uwt(new_y, wf, k, levels)
# Matrix of the difference between each wavelet level and the original data
diff_array = np.array([(wave.iuwt(wt[i:i+1], wf, k)-new_y) for i in range(len(wt))])
# Index of the level which is most similar to original data (to obtain smoothed data)
indx = np.argmin(np.sum(diff_array**2, axis=1))
# Use the wavelet levels around this region
noise_wt = wt[indx:indx+1]
# smoothed data in 2^n length
new_y = wave.iuwt(noise_wt, wf, k)
# Background Removal
error = 10000
errdiff = 100
i = -1
iter_y_dict = {0:np.copy(new_y)}
bkg_approx_dict = {0:np.array([])}
while abs(errdiff)>=1*10**-24:
i += 1
# Wave transform
wt = wave.uwt(iter_y_dict[i], wf, k, levels)
# Assume last slice is lowest frequency (background approximation)
bkg_wt = wt[-3:-1]
bkg_approx_dict[i] = wave.iuwt(bkg_wt, wf, k)
# Get the error
errdiff = error - sum(iter_y_dict[i] - bkg_approx_dict[i])**2
error = sum(iter_y_dict[i] - bkg_approx_dict[i])**2
# Make every peak higher than bkg_wt
diff = (new_y - bkg_approx_dict[i])
peak_idxs_to_remove = np.where(diff>0.)[0]
iter_y_dict[i+1] = np.copy(new_y)
iter_y_dict[i+1][peak_idxs_to_remove] = np.copy(bkg_approx_dict[i])[peak_idxs_to_remove]
# new data without noise and background
new_y = new_y[orig_mask]
bkg_approx = bkg_approx_dict[len(bkg_approx_dict.keys())-1][orig_mask]
new_data = diff[orig_mask]
##############################################################
# plot the data and results
fig = plt.figure()
ax_raw_data = fig.add_subplot(121)
ax_WT = fig.add_subplot(122)
ax_raw_data.plot(xy['x'], xy['y'], 'g')
for bkg in bkg_approx_dict.values():
ax_raw_data.plot(xy['x'], bkg[orig_mask], 'k')
ax_WT.plot(xy['x'], new_data, 'y')
fig.tight_layout()
plt.show()
这里是我现在得到的输出： 
正如你所看到的，背景消除仍然存在问题（在每次迭代后它都会向右移动），但这是我将在此讨论的一个不同的问题。
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