Generate a random double in a range

I have two doubles like the following

double min = 100;
double max = 101;

and with a random generator, I need to create a double value between the range of min and max.

Random r = new Random();
r.nextDouble();

but there is nothing here where we can specify the range.

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要在rangeMin和rangeMax之间生成一个随机值：

Random r = new Random();
double randomValue = rangeMin + (rangeMax - rangeMin) * r.nextDouble();

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This question was asked before Java 7 release but now, there is another possible way using Java 7 (and above) API:

double random = ThreadLocalRandom.current().nextDouble(min, max);

nextDouble will return a pseudorandom double value between the minimum (inclusive) and the maximum (exclusive). The bounds are not necessarily int , and can be double .

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Use this:

double start = 400;
double end = 402;
double random = new Random().nextDouble();
double result = start + (random * (end - start));
System.out.println(result);

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EDIT:

new Random().nextDouble() : randomly generates a number between 0 and 1.

start : start number, to shift number "to the right"

end - start : interval. Random gives you from 0% to 100% of this number, because random gives you a number from 0 to 1.

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EDIT 2: Tks @daniel and @aaa bbb. My first answer was wrong.

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