Getting a 403 error after upgrading to php5.5

OK I am new to ASKING questions on stackoverflow, but I need to get this figured out. I have a VPS with Apache installed Running Ubuntu 12.04 LTS. I downloaded a php script which required php 5.4+ but I had 5.3 installed. Then I followed the instructions located at this link. While doing the upgrade, the installer told me that my php.ini file was manually changed. I believe I did this in ord

升级到php5.5后出现403错误

好的,我是在stackoverflow上提出问题的新手,但我需要弄清楚这一点。 我安装了Apache的VPS运行Ubuntu 12.04 LTS。 我下载了一个php脚本,它需要php 5.4+,但我安装了5.3。 然后我按照此链接中的说明操作。 在进行升级时,安装程​​序告诉我,我的php.ini文件是手动更改的。 我相信我这么做是为了在很久以前用“display_errors = on”变量查看屏幕上的错误。 因此,我选择了保留和使用旧版本php.ini的选项。 一旦安装完成并

PHP 5.4.12 Mac OSX imagecreate* functions not working

I am running PHP 5.4.12 from macports on Mac OSX 10.7.5 with Apache 2 (Apache/2.2.24 (Unix) mod_ssl/2.2.24 OpenSSL/1.0.1e DAV/2 PHP/5.4.12). 5 days ago this code worked (yes directly from PHP site): <?php header ('Content-Type: image/png'); $im = @imagecreatetruecolor(120, 20) or die('Cannot Initialize new GD image stream'); $text_color = imagecolorallocate($im, 233, 14, 91); imagestri

PHP 5.4.12 Mac OSX imagecreate *函数无效

我在Mac OS X 10.7.5上使用Apache 2(Apache / 2.2.24(Unix)mod_ssl / 2.2.24 OpenSSL / 1.0.1e DAV / 2 PHP / 5.4.12)从macports运行PHP 5.4.12。 5天前此代码工作(是直接从PHP网站): <?php header ('Content-Type: image/png'); $im = @imagecreatetruecolor(120, 20) or die('Cannot Initialize new GD image stream'); $text_color = imagecolorallocate($im, 233, 14, 91); imagestring($im, 1, 5, 5, 'A

Packaging a LAMP application for easy deployment

I'm the resident "computer guy" for my mom's small business. About a year ago I set up a spare Dell box as an Ubuntu server sitting on the LAN in the shop, set up a LAMP stack on it and built a few intranet web applications (mostly with PHP and MySQL) for things like managing customer rewards data, inventory, employee timelogs, etc. I went on to implement a custom barcode-and-c

打包LAMP应用程序以便于部署

我是我妈妈小企业的居民“电脑人”。 大约一年前,我在店里的局域网上安装了一个备用Dell服务器作为Ubuntu服务器,在其上建立了一个LAMP堆栈,并构建了一些内部网络Web应用程序(主要是PHP和MySQL),用于管理客户奖励数据,库存,员工时间记录等。我接着实现了一个自定义的条形码和烹饪指令标签生成器,其前端可以在Avery模板上打印,还有一个完整的现金出纳前端,条形码扫描,库存定制挂钩管理和一套会计报告。 我的小数据库应

PHP upgrade to v.5.3 breaks includes?

I was asked to fix a site that was fine just days ago and now is not able to include files due to the host's upgrade of the PHP to v.5.3 For each include I now get two Warnings, like this: Warning: include_once(file.php) [function.include-once]: failed to open stream: No such file or directory in /home/content/anotherFile.inc.php on line 2 Warning: include_once() [function.include]: Fai

PHP升级到v.5.3的突破包括?

我被要求修复一个在几天前已经很好的网站,现在由于主机将PHP升级到了v.5.3,因此无法包含文件 对于每个包含我现在得到两个警告,像这样: 警告:include_once(file.php)[function.include-once]:未能打开流:第2行中的/home/content/anotherFile.inc.php中没有这样的文件或目录 警告:include_once()[function.include]:在/home/content/anotherFile.inc.php文件中打开'file.php'失败(include_path ='

php.ini reload in php

I have php script that must be runned from console (php-cli). But configuration of php.ini for php-cli was incorrect. I fix it, but when I run script a had error with php config, because php.ini uses an old. How I can reload php.ini for console without restart server? 每次从CLI调用PHP时,配置都会被新加载。

php.ini在PHP中重新加载

我有php脚本,必须从控制台运行(php-cli)。 但是php-cli的配置不正确。 我修复它,但是当我运行脚本时,php配置出错,因为php.ini使用了旧的。 如何重新加载php.ini的控制台无需重新启动服务器? 每次从CLI调用PHP时,配置都会被新加载。

where can I find the php.ini for php

It appears that the php command line is using a different php.ini from the main php interpreter. I am using Ubuntu 10.4. My problem is that in the main php.ini I have included an extra path for an external library, but in the cli version this is not present, and so I have a path inclusion error. thanks 只要问一下PHP: $ php -i |grep php.ini Better yet: $ php --ini This will also show all

我在哪里可以找到PHP的php.ini

看来,PHP的命令行是使用主要的PHP解释器不同的php.ini。 我使用Ubuntu 10.4。 我的问题是,在主要的php.ini中,我为外部库包含了一个额外的路径,但是在cli版本中,这个不存在,所以我有一个路径包含错误。 谢谢 只要问一下PHP: $ php -i |grep php.ini 更好的是: $ php --ini 这也会显示所有加载的* .ini文件(通常挂在debian中的一些conf.d目录中): 配置文件(php.ini)路径:/ etc / php5 / cli 加载的配置

How to find the php.ini file used by the command line?

I need to enable pdo_mysql in my EasyPhp environment, so I went to php.ini file and uncommented the following line: extension=php_pdo_mysql.dll Unfortunately I still have the same problem. I'm using the CLI so I suppose I need to locate the php.ini file used by the CLI. How can I find it? 只需运行php --ini You can get a full phpinfo() using : php -i And, in there, there is the php.in

如何找到命令行使用的php.ini文件?

我需要在我的EasyPhp环境中启用pdo_mysql,所以我去了php.ini文件并取消注释以下行: extension=php_pdo_mysql.dll 不幸的是我仍然有同样的问题。 我正在使用CLI,所以我想我需要找到CLI使用的php.ini文件。 我怎么找到它? 只需运行php --ini 您可以使用以下方法获得完整的phpinfo() : php -i 并且,在那里,使用了php.ini文件: $ php -i | grep 'Configuration File' Configuration File (php.ini) Path => /etc

Removing a nested array out of a array and assigning to a new variable in php

Okay so i read about multi-dimensional arrays but my problem is such, i am deserializing a JSON string into a php array and the output is such when decoded. Now i want to assign comparisionResultDTOarr to a new array. The name of the array is $data array (size=1) 0 => object(stdClass)[1] public 'class' => string 'com.ofss.fc.app.ops.config.response.CompareDomainObjectRespons

从数组中移除一个嵌套数组并在php中分配一个新变量

好吧,所以我读了多维数组,但我的问题是这样的,我反序列化一个JSON字符串到一个PHP数组和解码输出。 现在我想将comparisionResultDTOarr分配给一个新数组。 数组的名称是$ data array (size=1) 0 => object(stdClass)[1] public 'class' => string 'com.ofss.fc.app.ops.config.response.CompareDomainObjectResponse' (length=63) public 'comparisonResultDTOarr' => array (size=24

puzzled by format of PHP multi dimensional array

Sorry if this is a duplication of anyone elses question but in my eyes it doesn't appear to match any other PHP multi dimensional array questions on here. And I've read them all. :-( I'm trying to access values of this array (which I have no control over). But it's format is puzzling me and as yet I can't get at the values how I thought I should be able to. This my JSON

对PHP多维数组格式感到困惑

对不起,如果这是任何人的elses问题的重复,但在我看来,它似乎不匹配任何其他PHP多维数组问题在这里。 我已经阅读了所有内容。 :-( 我试图访问这个数组的值(我无法控制)。 但它的格式令我感到困惑,至今我无法理解我认为我应该能够做到的价值观。 这是我的JSON数组示例。 {"Result":[{"Links":[{"UrlTo":"blahblahA/","Visited":1380104406,"FirstSeen":1375979058,"PrevVisited":1379817016,"Anchor":"text links","

utf 8

I have a symfony app that uses the json_encode and json_decode to keep a record of some prices. The problem is that json_decode works OK in one file (I can decode the string stored in my PSQL database), but when I call it from other file json_decode returns null, I've check the file encodings (all are utf-8) the tables and database encoding(utf-8 too). So I don't know where the problem

utf 8

我有一个symfony应用程序,它使用json_encode和json_decode来记录一些价格。 问题是json_decode在一个文件中工作正常(我可以解码存储在我的PSQL数据库中的字符串),但是当我从其他文件调用它时, json_decode返回null,我检查了文件编码(全部是utf-8)表和数据库编码(UTF-8)。 所以我不知道问题出在哪里,也尝试过utf8_encode() ... 任何帮助将不胜感激。 谢谢。 这里是有效的编码json(这是一个由php json_encode编