I have an grayscale image of a comic strip page that features several dialogue bubbles (=speech baloons, etc), that are enclosed areas with white background and solid black borders that contain text inside, ie something like that: I want to detect these regions and create a mask (binary is ok) that will cover all the inside regions of dialogue bubbles, ie something like: The same image, mask
我有一个带有几个对话泡泡（=语音聊天室等）的漫画页面的灰度图像，它们是带有白色背景的封闭区域和包含文本的纯黑色边框，即类似的东西： 我想检测这些区域并创建一个掩码（二进制就可以），它将覆盖对话气泡的所有内部区域，例如： 相同的图像，掩码覆盖，要完全清楚： 所以，我对算法的基本概念是这样的： 检测文本的位置 - 在每个气泡中至少放置一个像素。 稍微扩大这些地区并采用门槛来获得更好的起点; 我已经完
I am writing web app using Flask(Python3.4) & psycopg2 to connect to postgres 9.4 database. I have option in my web app where user can write their own query and execute it using web app and get output in html table in response. I'm using cursor as conn.cursor(cursor_factory=psycopg2.extras.DictCursor) Which i can not change as it is used by other parts of web app also. One of my use
我正在使用Flask（Python3.4）＆psycopg2编写web应用程序来连接到postgres 9.4数据库。 我可以在我的web应用程序中选择用户可以编写自己的查询并使用web应用程序执行它，并在html表中获取输出作为响应。 我使用游标作为conn.cursor（cursor_factory = psycopg2.extras.DictCursor）我不能改变，因为它也被其他部分的web应用程序使用。 我的一位用户像下面这样写了SQL， SELECT name || ' - ' || address, id, salary || ';
I'm using virtualenv and I need to install "psycopg2". I have done the following: pip install http://pypi.python.org/packages/source/p/psycopg2/psycopg2-2.4.tar.gz#md5=24f4368e2cfdc1a2b03282ddda814160 And I have the following messages: Downloading/unpacking http://pypi.python.org/packages/source/p/psycopg2/psycopg2 -2.4.tar.gz#md5=24f4368e2cfdc1a2b03282ddda814160 Downloading
我使用的是virtualenv ，我需要安装“psycopg2”。 我做了以下工作： pip install http://pypi.python.org/packages/source/p/psycopg2/psycopg2-2.4.tar.gz#md5=24f4368e2cfdc1a2b03282ddda814160 我有以下信息： Downloading/unpacking http://pypi.python.org/packages/source/p/psycopg2/psycopg2 -2.4.tar.gz#md5=24f4368e2cfdc1a2b03282ddda814160 Downloading psycopg2-2.4.tar.gz (607Kb): 607Kb downloaded Runni
Trying to embed a python interpreter into a c++ application. Thought it would be straight forward, but I am having trouble I think with linking. The only unusual thing is that I am trying to use a specific Anaconda package. The simple c++ code is: # include <Python.h> int main() { printf("before initialize"); Py_Initialize(); printf("after initialize"); PyRun_SimpleStri
尝试将python解释器嵌入到c ++应用程序中。 认为这将是直截了当的，但我有麻烦，我认为与链接。 唯一不寻常的是我正在尝试使用特定的Anaconda软件包。 简单的c ++代码是： # include <Python.h> int main() { printf("before initialize"); Py_Initialize(); printf("after initialize"); PyRun_SimpleString("print('Hello from Python')"); Py_Finalize(); return 0; } 编译我使用： gcc
How do I get the signature of built in methods? Example: dict().get(k) >> a = dict().get >> a <built-in method get of dict object at 0x1003aafd0> >> a.__doc__ 'D.get(k[,d]) -> D[k] if k in D, else d. d defaults to None.' >> import inspect >> inspect.getargspec(a) TypeError: <built-in method get of dict object at 0x100377250> is not a Python function
我如何获得内置方法的签名？ 例如：dict（）。get（k） >> a = dict().get >> a <built-in method get of dict object at 0x1003aafd0> >> a.__doc__ 'D.get(k[,d]) -> D[k] if k in D, else d. d defaults to None.' >> import inspect >> inspect.getargspec(a) TypeError: <built-in method get of dict object at 0x100377250> is not a Python function 我希望看到这样的
Given the following models.py class Parent(models.Model): name = models.CharField(max_length=100) class Child(models.Model): parent = models.ForeignKey('Parent', related_name='children') status = models.CharField(max_length=10, choices=(('ok', 'ok'), ('fail', 'fail'))) I would like access on the parent model/view to the grouped counts of the parent's children. eg parent.num_
鉴于以下models.py class Parent(models.Model): name = models.CharField(max_length=100) class Child(models.Model): parent = models.ForeignKey('Parent', related_name='children') status = models.CharField(max_length=10, choices=(('ok', 'ok'), ('fail', 'fail'))) 我想访问父级模型/视图到父级孩子的分组计数。 例如 parent.num_ok, parent.num_failed 要么 parent.child_counts_per_status['o
As noted in other questions, Django experts like Two Scoops recommend explicit OneToOneFields rather than multi-table inheritance to avoid performance penalties of implicit joins. I have tried to follow such an approach, and my design is actually object composition, but have a few questions. All three of these are concrete tables. class Widget: ... many shared fields ... class FunWidget:
正如其他问题所述，像Two Scoops这样的Django专家建议使用显式的OneToOneFields而不是多表继承来避免隐式联接的性能损失。 我试图遵循这种方法，而我的设计实际上是对象组合，但有几个问题。 所有这三个都是具体的表格。 class Widget: ... many shared fields ... class FunWidget: parent = models.OneToOneField(Widget, related_name='child', primary_key=True) ... fun-specific fields ... class WorkWidget:
I'm building an app that puts together the hardware of a computer. This is my first time working with django. Say I have the following models: class Memory(models.Model): partNum = models.CharField() capacity = models.CharField() class Computer(models.Model): name = models.CharField() memory = models.ManyToManyField(Memory) # also has cpus, hard drives, and motherboard
我正在构建一个将计算机的硬件放在一起的应用程序。 这是我第一次与Django合作。 假设我有以下型号： class Memory(models.Model): partNum = models.CharField() capacity = models.CharField() class Computer(models.Model): name = models.CharField() memory = models.ManyToManyField(Memory) # also has cpus, hard drives, and motherboard, but focus on memory for now 一个内存对象可以属于
I have a table containing about 30k records, that I'm attempting to iterate over and process with Django's ORM. Each record stores several binary blobs, which can each be several MB in size, that I need to process and write to a file. However, I'm having trouble using Django for this because of memory constraints. I have 8GB of memory on my system, but after processing about 5k of
我有一个包含大约30k条记录的表，我试图迭代并使用Django的ORM进行处理。 每个记录存储几个二进制blob，每个二进制blob的大小都可以是几MB，我需要处理并写入一个文件。 但是，由于内存限制，我在使用Django时遇到了麻烦。 我的系统上有8GB的内存，但是在处理大约5K条记录后，Python进程占用了全部8GB，并被Linux内核杀死。 我已经尝试过各种技巧来清除Django的查询缓存，如： 定期调用MyModel.objects.update() 设置se
Is there any easy way / library / external app to introduce Unit of Work concept to Django ORM? What approaches or techniques do you use to solve the problem of importing the same row twice in a complicated model setup without loosing all the modularity? EDIT Example Consider the following examplatory situation - there is a model Location which has a relationship with itself called route t
有没有简单的方法/库/外部应用程序将工作单元概念引入Django ORM？ 您使用什么方法或技术来解决在复杂模型设置中两次导入同一行而不丢失所有模块性的问题？ 编辑 例 考虑以下例证情况 - 有一个模型Location与自身有关系，称为通过附加模型Route 。 现在假设每条Route都有一些属性，称为： entry_fare （您需要为进入路线支付的金额）和exit_fare （您在另一端退出路线时需要支付的金额）。 现在让我们假设你想要实施一