I have set the path to a newly created Firefox profile in Ubuntu OS using python & Selenium. But when I run the python script I am getting an error OSError: [Errno 13] Permission denied I have changed the permissions on the file to 755 and I am still getting the error and also tried sudo. sudo chmod 775 /home/student/.mozilla/firefox/gwi6uqpe.Default User2/ This is the start of my pyth
我已经使用python＆Selenium设置了在Ubuntu OS中新创建的Firefox配置文件的路径。 但是当我运行Python脚本时，我收到一个错误 OSError: [Errno 13] Permission denied 我已将文件的权限更改为755，并且仍然收到错误并尝试了sudo。 sudo chmod 775 /home/student/.mozilla/firefox/gwi6uqpe.Default User2/ 这是我的python脚本的开始： - from selenium import webdriver from selenium.webdriver.common.keys import Key
Per this previous question I updated Selenium to version 2.0.1 But now I have another error, even when the profile files exist under /tmp/webdriver-py-profilecopy : File "/home/sultan/Repository/Django/monitor/app/request.py", line 236, in perform browser = Firefox(profile) File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/firefox/webdriver.py", line 46, in __init__ se
根据以前的问题，我将Selenium更新到了2.0.1版。但是现在我又遇到了另一个错误，即使配置文件存在于/tmp/webdriver-py-profilecopy ： File "/home/sultan/Repository/Django/monitor/app/request.py", line 236, in perform browser = Firefox(profile) File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/firefox/webdriver.py", line 46, in __init__ self.binary, timeout), File "/usr/local
In Python, the following code snippet will open an interactive shell upon execution. import code; code.interact(local = locals()) This has proved tremendously useful for debugging in quite a bit of code that is poorly documented. One can use the shell to navigate the in-program environment and figure out what's going on, even without a debugger. So far, so good. Now the challenge. The
在Python中，以下代码片段将在执行后打开交互式shell。 import code; code.interact(local = locals()) 这已被证明对于调试很多文档记录不佳的代码非常有用。 人们可以使用shell来浏览程序内环境并找出发生了什么，即使没有调试器。 到现在为止还挺好。 现在是挑战。 我使用的软件（顺便说就是用Django编写的）使用某种调度机制，然后再与另一个Python进程交流，除了编辑代码之外，我无法控制它。 除了发送给它进行处理
I can't run my PyCharm IDE using port 80. I need to use PayPal that requires me to use port 80. But using Mac OS X 10.8 I can't have it working because of permission issues. I've already tried running PyCharm with SUDO command. Does anyone know how to run Pycharm using port 80, or any other solution? Thanks. For the ones who are looking for the answer of this question, please c
我无法使用端口80运行我的PyCharm IDE。我需要使用PayPal，它要求我使用端口80.但是，使用Mac OS X 10.8时，由于权限问题，我无法使用它。 我已经尝试用SUDO命令运行PyCharm。 有谁知道如何使用端口80或任何其他解决方案来运行Pycharm？ 谢谢。 对于那些正在寻找这个问题的答案的人，请检查你的Pycharm运行/调试配置。 运行 - >编辑配置 - >端口 要赋予PyCharm权限，必须以Administor（Windows）运行，或者在OSX
I want to download packages using pip like pandas,numpy, tensorflow, keras . Since I am under corporate network connection I am unable to install directly. I used all the solutions on stackoverflow.. nothing seems to work out . When i used this chrome://net-internals/#proxy , this didn't give me any proxy server address and port number. Instead it gave .PAC script Effective proxy settin
我想用像pandas，numpy，tensorflow，keras等pip来下载软件包。 由于我在公司网络连接下，因此无法直接安装。 我在stackoverflow上使用了所有的解决方案..似乎没有什么可以解决的。 当我使用这个chrome://net-internals/#proxy ，这并没有给我任何代理服务器地址和端口号。 相反，它给了.PAC脚本 Effective proxy settings PAC script: *****.pac Source: SYSTEM 1）我使用了这里的解决方案 ipconfig /all | find /i "Dn
Some time ago, someone on SO asked how to retrieve a list of words for a given synset using NLTK's wordnet wrapper. Here is one of the suggested responses: for synset in wn.synsets('dog'): print synset.lemmas[0].name Running this code with NLTK 3.0 yields TypeError: 'instancemethod' object is not subscriptable . I tried each of the previously-proposed solutions (each of the s
前段时间，SO上的某人问了如何使用NLTK的wordnet wrapper来检索给定synset的单词列表。 这是建议的回应之一： for synset in wn.synsets('dog'): print synset.lemmas[0].name 使用NLTK 3.0运行此代码会产生TypeError: 'instancemethod' object is not subscriptable 。 我尝试了以前提出的每个解决方案（上面链接的页面中描述的每个解决方案），但每个解决方案都会引发错误。 因此，我想问一下：是否可以打印
Situation: You have an image with 1 main color and you need to convert it to another based on a given rgb value. Problem: There are a number of different, but similar shades of that color that also need to be converted, which makes a simple 'change-all-(0,0,0)-pixels-to-(0,100,200)' solution worthless. If anyone can point me in the right direction as far as an algorithm or an imag
情况： 你有一个主色的图像，你需要根据给定的rgb值将它转换为另一个。 问题： 有许多不同但相似的颜色也需要转换，这使得简单的“全部变化（0,0,0）像素到（0,100,200）”解决方案变得毫无价值。 如果任何人都可以指向正确的方向，只要算法或图像处理技术可以让这项任务更加易于管理，那就太棒了。 我一直在使用PIL来尝试这个问题，但任何一般的技巧都会很好。 编辑： 此外，我已经使用了这个其他的答案（用Python
I'm using mechanize in Python to grab some data from a website and send it new data. The thing is that the site is in French, so I get question marks in a diamond shape ( ) instead of various characters such as éÉÀàùÙîû and others. I tried looking around on Google and StackOverflow and found various answers that didn't fix my problem. I've seen answers recommending trying one of
我在Python中使用机械化从网站获取一些数据并发送新数据。 事情是这个网站是法文的，所以我用钻石形状（ ）代替各种角色，例如éÉààùÙîû和其他人。 我试着环顾Google和StackOverflow，发现并没有解决我的问题的各种答案。 我已经看到了建议尝试以下某一行的答案： myString = éÀî myString.encode('latin-1') myString.encode('iso-8859-1') unicode(myString, 'iso-8859-1') 但似乎没有一个工作。 我需要这种情况的两
I am working on Django 1.8. I want to work with Django-blog-zinnia. I have installed zinnia, changed my setting.py file and have added links in urls.py of project. when I tried to access zinnia using weblog as per mentioned on Installation site weblog I got an error 'zinnia_loop_template' received too many positional arguments I am new to it. Kindly tell me how to resolve this
我正在研究Django 1.8。 我想与Django-blog-zinnia一起工作。 我已经安装了百日草，更改了我的setting.py文件，并在项目的urls.py中添加了链接。 当我尝试使用安装站点上提到的weblog访问百日咳时 博客 我有一个错误 'zinnia_loop_template'收到太多的位置参数 我对它很陌生。 请告诉我如何解决这个问题 这是我的setting.py文件“”“ 新项目项目的Django设置。 由'django-admin startproject'使
I am a newbie in Django 1.9.5 and using windows as my platform. I have a problem to link my css, images and js to django templage, Here is my project structure Here is my settings page BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__))) PROJECT_DIR = os.path.dirname(__file__) STATIC_ROOT = os.path.join(BASE_DIR, 'static') STATIC_URL = '/static/' STA
我是Django 1.9.5的新手，并使用Windows作为我的平台。 我有一个问题，将我的CSS，图像和js链接到django templage， 这是我的项目结构 这是我的设置页面 BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__))) PROJECT_DIR = os.path.dirname(__file__) STATIC_ROOT = os.path.join(BASE_DIR, 'static') STATIC_URL = '/static/' STATICFILES_DIRS = ( os.path.join(BAS