Python unittest ignore numpy

I am writing python tests with unittest and running the tests from the command line with nosetests --with-coverage -x When I include numpy in one of my tests it tries to test the numpy packages as well. Example output: ... Name Stmts Miss Cover Missing ------------------------------------------------------------- CLOCK 39 33

Python单元测试忽略numpy

我正在用unittest编写python测试,并使用命令行运行测试 nosetests --with-coverage -x 当我在我的一个测试中包含numpy时,它也会尝试测试numpy包。 示例输出: ... Name Stmts Miss Cover Missing ------------------------------------------------------------- CLOCK 39 33 15% 3, 7-13, 17, 20-25, 28-47 LFU 4

Error: No module named cv2

I have already found few questions at SO but i am unable to solve this problem using the answers there. I am new to python. I am having python in Ubuntu 12.04. In my /usr/local/lib , there are two python folders python 2.7 and python 3.2 . python 2.7 contains dist-packages and site-packages while python 3.2 contains only dist-packages. I am trying to run a very simple opencv example with t

错误:没有名为cv2的模块

我已经在SO上发现了几个问题,但我无法使用那里的答案来解决这个问题。 我是python的新手。 我在Ubuntu 12.04中使用python。 在我的/usr/local/lib ,有两个python文件夹python 2.7和python 3.2 。 python 2.7包含dist-packages和site-packages,而python 3.2只包含dist-packages。 我想用下面的代码运行一个非常简单的opencv示例: import cv2 import numpy as np from matplotlib import pyplot as plt img = cv2.imre

How to detect minimum version of python that a script required

I have built an application with python. How can I detect minimum version of Python that my application needs? Like Django , in that website it tells you the minimum version of python that it required (example: 2.6.6 and later). It means I wanna tell to user what minimum version of python he should install on his system There isn't really an automated way to check what features your co

如何检测脚本所需的最低版本的python

我用python构建了一个应用程序。 我如何检测我的应用程序需要的最低版本的Python? 和Django一样,在那个网站上它会告诉你它需要的最低版本的python(例如:2.6.6和更高版本)。 这意味着我想告诉用户他应该在他的系统上安装哪些最低版本的python 没有真正的自动化方法来检查您的代码正在使用哪些功能,并将其与特定的Python版本相关联。 如果您的代码依赖于已修复的bug或其他关键字,则版本检测将更加困难。 一般来说

Cant pass object variable to object method as default value

This question already has an answer here: How to pass a default argument value of an instance member to a method? 3 answers 尝试这个class TrabGraph: def circle(self): print (self.radius) def __init__(self,radius): self.radius = radius TrabGraph(2).circle()

无法将对象变量作为默认值传递给对象方法

这个问题在这里已经有了答案: 如何将实例成员的默认参数值传递给方法? 3个答案 尝试这个class TrabGraph: def circle(self): print (self.radius) def __init__(self,radius): self.radius = radius TrabGraph(2).circle()

Python private class variables that aren't class variables

When trying to access __variables from a class, the parser assumes the 2 underscores are private relative to the current class. Notice how an unrelated function gets a "private" variable. Is this a bug? >>> def f(): pass ... >>> class A: ... def g(self): ... f.__x = 1 ... def h(): ... pass ... h.__y = 2 ... ret

不是类变量的Python私有类变量

当试图从类中访问__variables ,解析器假定2个下划线相对于当前类是私有的。 注意一个不相关的函数如何得到一个“私有”变量。 这是一个错误? >>> def f(): pass ... >>> class A: ... def g(self): ... f.__x = 1 ... def h(): ... pass ... h.__y = 2 ... return h ... >>> z = A().g() >>> dir(z) ['_A__y', '__call__', '__class__', '__delatt

Multiprocessing : NULL result without error in PyObject

Here is a sample program where I use multiprocessing. The calculations are done with multiprocessing.Process and the results are collected using multiprocessing.Queue . #THIS PROGRAM RUNS WITH ~40Gb RAM. (you can reduce a,b,c for less RAM #but then it works for smaller values) #PROBLEM OCCURS ONLY FOR HUGE DATA. from numpy import * import multiprocessing as mp a = arange(0, 3500, 5) b = ar

多处理:在PyObject中没有错误的NULL结果

这里是我使用多处理的示例程序。 计算是通过multiprocessing.Process完成的。 multiprocessing.Process和结果是​​使用multiprocessing.Queue收集的。 #THIS PROGRAM RUNS WITH ~40Gb RAM. (you can reduce a,b,c for less RAM #but then it works for smaller values) #PROBLEM OCCURS ONLY FOR HUGE DATA. from numpy import * import multiprocessing as mp a = arange(0, 3500, 5) b = arange(0, 3500, 5) c = arange(0

How to execute multiple tasks in parallel in fabric

I know that by using -P switch or @parallel tag I can run task in parallel on multiple hosts. I'm trying to execute multiple long running tasks in parallel on the same host: @task def task1(): # long running op @task def task2(): #long running op @task def task3(): #long running op @task def backup_all(): execute(task1) execute(task2) execute(task3) How can I start task1, t

如何在结构中并行执行多个任务

我知道通过使用-P开关或@parallel标签,我可以在多台主机上并行运行任务。 我试图在同一主机上并行执行多个长时间运行的任务: @task def task1(): # long running op @task def task2(): #long running op @task def task3(): #long running op @task def backup_all(): execute(task1) execute(task2) execute(task3) 如何通过使用fabric在同一主机上并行启动task1,task2和task3。 我知道我可以用不同的

why idle in virtualenv keeps using system one?

I have create a local python installation in ~/localpython/python276 After create a virtualenv as py276, I linked the idle to ~/localpython/python276 /bin/idle . I also activated the py276. $ which python /home/xxx/virtualenvs/py276/bin/python $ python Python 2.7.6 [GCC 4.6.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. $ bin/idle Python 2.7.6 [GCC 4.6.3

为什么在virtualenv中闲置一直使用系统?

我在〜/ localpython / python276中创建了一个本地python安装在创建一个virtualenv作为py276后,我将空闲链接到了~/localpython/python276 /bin/idle 。 我也激活了py276。 $ which python /home/xxx/virtualenvs/py276/bin/python $ python Python 2.7.6 [GCC 4.6.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. $ bin/idle Python 2.7.6 [GCC 4.6.3] on linux2 Type "copyright",

How does symlinking work in linux

I installed django framework and going through the documentation I was instructed to run the django-admin.py but threw an error: Command not found I was Instructed in the documentation to try symlinking to django-admin.py from some place on my path such as /usr/local/bin which has left me totally confused because I'm kind of new to linux A symlink is a symbolic link . What you're

symlinking在linux中如何工作

我安装了django框架,并通过指导我运行django-admin.py的文档,但抛出了一个错误: Command not found 我被指示在文档中尝试从我的路径上的某个地方对django-admin.py进行符号链接,例如 /usr/local/bin 这让我完全感到困惑,因为我对linux很陌生 符号链接是一个符号链接 。 你正在做的是告诉操作系统,当请求进入路径x时,将其视为路径y。 因此,如果django需要'/ expected / path / to / file'中的文件,但

No module named SCons.Script‏

I have been trying to get SCons working now for quite a time, but didn't succeed yet. Before everything else: I'm running Windows 7 x64. I have firstly installed Python 2.7.11 in C:SoftwarePython27 and added both that directory as C:SoftwarePythonScripts to the system path (for all users, that is). Then I installed SCons in C:SoftwarePython27Libsite-packagesscons-2.4.1 , and the scrip

没有名为SCons.Script的模块

我一直试图让SCons工作一段时间,但还没有成功。 在开始之前:我正在运行Windows 7 x64。 我首先在C:SoftwarePython27安装了Python 2.7.11,并将该目录作为C:SoftwarePythonScripts到系统路径(即所有用户)。 然后,我在C:SoftwarePython27Libsite-packagesscons-2.4.1安装了SCons,并在前面提到的脚本目录(SCons安装msi默认的目录)中安装了脚本。 现在,当我尝试运行SCons时,出现以下错误消息: 导入失败。 无法在