Write in json file with Python

This question already has an answer here: Parsing values from a JSON file? 7 answers I keep in mind 4 methods while I work with JSON objects in python. json.dumps(<a python dict object>) - gives a string representation of json formed out of the python dict object json.dump( <a python dict object>,<file obj>) - writes a json file in file object json.loads(<a string&

用Python写入json文件

这个问题在这里已经有了答案: 从JSON文件解析值? 7个答案 我在使用python中的JSON对象时记住了4个方法。 json.dumps(<a python dict object>) - 给出了由python dict对象构成的json的字符串表示形式 json.dump( <a python dict object>,<file obj>) - 在文件对象中写入一个json文件 json.loads(<a string>) - 从字符串读取json对象 json.load(<a json file>) - 从文件读取json对象

Collecting a value from Json

This question already has an answer here: Parsing values from a JSON file? 7 answers After decoding with the json module, this is just a dictionary containing lists and strings and other dictionaries: import json json_result = json.loads(json_string) id = json_result['data'][0]['id'] Demo: >>> import json >>> sample = ''' ... { ... "status": "success", ... "data

从Json收集一个值

这个问题在这里已经有了答案: 从JSON文件解析值? 7个答案 用json模块解码后,这只是一个包含列表和字符串以及其他字典的字典: import json json_result = json.loads(json_string) id = json_result['data'][0]['id'] 演示: >>> import json >>> sample = ''' ... { ... "status": "success", ... "data": [ ... { ... "notes": [], ... "handles": { ..

Using python how can i convert json to array list

This question already has an answer here: Parsing values from a JSON file? 7 answers There is the json module in python: import json with open("input.json") as json_file: data=json.load(json_file) for key, value in data.items(): print("json key: ", key) print("json value: ", str(value)) The json module will import the data into a python dict. Actually this dict is already a

使用Python如何将JSON转换为数组列表

这个问题在这里已经有了答案: 从JSON文件解析值? 7个答案 python中有json模块: import json with open("input.json") as json_file: data=json.load(json_file) for key, value in data.items(): print("json key: ", key) print("json value: ", str(value)) json模块将数据导入python字典。 实际上,这个字典已经是一个树状数据结构。 它不提供给父母/孩子的经典指针。 但我认为你会发现Python的循

Creating lists and dictionaries from JSON data in Python

This question already has an answer here: Parsing values from a JSON file? 7 answers from_this = {"version":"0.0","response":[{"macAddress":"88:5A:92:A4:E7:C8","networkDeviceId":"e15789bd-47df-4df9-809f-daf81d15ff2a","lineCardId":"e5bddd56-2194-4b83-8ae5-597893800051","lastUpdated":"2014-06-03 01:39:19.855491-07","platformId":"C897VA-K9","vendor":"Cisco","numUpdates":1,"interfaceCount":"10","

在Python中从JSON数据创建列表和词典

这个问题在这里已经有了答案: 从JSON文件解析值? 7个答案 from_this = {"version":"0.0","response":[{"macAddress":"88:5A:92:A4:E7:C8","networkDeviceId":"e15789bd-47df-4df9-809f-daf81d15ff2a","lineCardId":"e5bddd56-2194-4b83-8ae5-597893800051","lastUpdated":"2014-06-03 01:39:19.855491-07","platformId":"C897VA-K9","vendor":"Cisco","numUpdates":1,"interfaceCount":"10","portRange":"ATM0, ATM0.1, BRI

The Fastest method to find element in JSON (Python)

This question already has an answer here: Parsing values from a JSON file? 7 answers Here's an easy way to do it: def function(json_object, name): for dict in json_object: if dict['name'] == name: return dict['price'] If you are sure that there are no duplicate names, an even more effective (and pythonic way to do it is to use list comprehensions: def function(

在JSON中查找元素的最快速方法(Python)

这个问题在这里已经有了答案: 从JSON文件解析值? 7个答案 这是一个简单的方法来做到这一点: def function(json_object, name): for dict in json_object: if dict['name'] == name: return dict['price'] 如果你确定没有重复的名字,那么更有效的(和pythonic的方法是使用列表解析: def function(json_object, name): return [obj for obj in json_object if obj['name']==name][0][

calculate the common exponent?

To explain this, this is basically a way to shrink floating point vector data into 8-bit or 16-bit signed or unsigned integers with a single common unsigned exponent (the most common of which being bs16 for precision with a common exponent of 11). I'm not sure what this pseudo-float method is called; all I know is to get the resulting float, you need to do this: float_result = int_value /

计算常用指数?

为了解释这一点,这基本上是一种将浮点向量数据缩小为8位或16位有符号或无符号整数的方法,其中一个公共无符号指数(其中最常见的是bs16 ,其精度为11,指数为11) 。 我不确定这个伪浮动方法被称为什么; 我所知道的是得到最终的浮点数,你需要这样做: float_result = int_value / ( 2.0 ** exponent ) 我想要做的就是匹配这些数据,通过尝试从给定的浮点数重新计算来基本猜测指数。 (如果做得好,它应该能够以其他格式

How to pipe live video frames from ffmpeg to PIL?

I need to use ffmpeg/avconv to pipe jpg frames to a python PIL (Pillow) Image object, using gst as an intermediary*. I've been searching everywhere for this answer without much luck. I think I'm close - but I'm stuck. Using Python 2.7 My ideal pipeline, launched from python, looks like this: ffmpeg/avconv (as h264 video) Piped -> gst-streamer (frames split into jpg) Pi

如何从ffmpeg管道直播视频帧到PIL?

我需要使用ffmpeg / avconv将jpg帧传输到python PIL(Pillow)图像对象,使用gst作为中介*。 我一直在寻找这个答案,没有多少运气。 我想我很接近 - 但我被卡住了。 使用Python 2.7 我从python启动的理想流水线如下所示: ffmpeg / avconv (如h264视频) 管道 - > gst-streamer (分割成jpg的帧) 管道 - > Pil图像对象 作为一个单一的命令,我可以控制前几个步骤,将硬编码所允许的.jpgs写入磁盘的速度

Vectorized Lookups of Pandas Series to a Dictionary

Problem Statement: A pandas dataframe column series, same_group needs to be created from booleans according to the values of two existing columns, row and col . The row needs to show True if both cells across a row have similar values (intersecting values) in a dictionary memberships , and False otherwise (no intersecting values). How do I do this in a vectorized way (not using apply)? Setu

熊猫系列矢量化查找到字典

问题陈述: 熊猫数据帧列系列中, same_group需要根据两个现有列( row和col的值从布尔值创建。 如果行中的两个单元格在字典memberships具有相似的值(相交值),则该行需要显示True,否则为False(不相交的值)。 我如何以矢量化的方式做到这一点(不使用apply)? 建立: import pandas as pd import numpy as np n = np.nan memberships = { 'a':['vowel'], 'b':['consonant'], 'c':['consonant'], 'd

Creating plot for black background presentation slides

I'm successfully using Python and Matplotlib to create transparent PNG figures that look good when I add the plots to a Powerpoint slide that has a white background. Below is an example: However, when I use a presentation slide deck that has a black background , the figure does not look as good. The text font and lines are all black, and they blend right into the background. Is there a

创建黑色背景演示文稿幻灯片的情节

我成功地使用Python和Matplotlib来创建透明的PNG图形,这些图形在将图形添加到具有白色背景的Powerpoint幻灯片时看起来不错。 下面是一个例子: 但是,当我使用黑色背景的演示幻灯片时 ,该图看起来不太好。 文字字体和线条都是黑色的,它们融合在背景中。 有没有一种快速简便的方法来生成这些数字,以便它们在黑色幻灯片上看起来很好? 例如,我想快速将所有的行和文本变成白色。 我知道我可以单独设置标题,轴标签,轴

Graphs not updating (matplotlib)

I'm trying to make a GUI that contains several figures, each with an axes (is 'axes' plural?). I managed to get the leftmost graph to plot upon initializing the respective widget using this line: self.leftImage = self.leftPlot.axes.imshow(self.defaultSlide, cmap = self.mymap) where self.leftPlot contains the necessary figure properties. I noticed that I didn't have to call

图表未更新(matplotlib)

我试图制作一个包含几个图形的GUI,每个图形都有一个坐标轴(是“坐标轴”的复数?)。 我使用这一行初始化相应的小部件时,设法得到最左边的图形: self.leftImage = self.leftPlot.axes.imshow(self.defaultSlide, cmap = self.mymap) self.leftPlot包含必要的图形属性。 我注意到,我不必为这部分调用plt.show()或其变体,我不知道它是否重要。 在后面的代码中,我调用了self.leftImage.set_data(newSlide) ,但即使