I have a simple scenario of publish a message to a SNS topic, which is subscribed by a SQS queue, but somehow the queue never receives the messages (ie, not show up in the SQS console). Here are the codes in Ruby: sns = Aws::SNS::Client.new; sqs = Aws::SQS::Client.new; q1 = sqs.create_queue({queue_name: "queue1”}); t1 = sns.create_topic({name: "topic1"}); q1_attr = sqs.get_queue_attributes({que
我有一个将消息发布到SQS队列订阅的SNS主题的简单场景，但不知何故队列从不接收消息（即，不会显示在SQS控制台中）。 以下是Ruby中的代码： sns = Aws::SNS::Client.new; sqs = Aws::SQS::Client.new; q1 = sqs.create_queue({queue_name: "queue1”}); t1 = sns.create_topic({name: "topic1"}); q1_attr = sqs.get_queue_attributes({queue_url: q1.queue_url,attribute_names: ["All"]}); s1 = sns.subscribe({topic_arn: t1.
I have an SQS queue which is subscribed to a SNS topic. When I publish a new notification to the topic, I use the following code (within a Sinatra app): jsonMessage = { "announcement" => { "first_name" => results['first_name'][:s], "last_name" => results['last_name'][:s], "loc_code" => results['location'][:s],
我有一个订阅了SNS主题的SQS队列。 当我向该主题发布新通知时，我使用以下代码（在Sinatra应用程序中）： jsonMessage = { "announcement" => { "first_name" => results['first_name'][:s], "last_name" => results['last_name'][:s], "loc_code" => results['location'][:s], "note" => params['note_content'
Questions Is there a best value to stay on so that I win the greatest percentage of games possible? If so, what is it? Edit: Is there an exact probability of winning that can be calculated for a given limit, independent of whatever the opponent does? (I haven't done probability & statistics since college). I'd be interested in seeing that as an answer to contrast it with my sim
问题 是否有最好的价值继续保持下去，以便我赢得尽可能多的比赛？ 如果是这样，那是什么？ 编辑：是否有一个确切的获胜概率，可以计算一个给定的限制，独立于任何对手的行为？ （自大学以来我没有做过概率统计）。 我有兴趣看到这个答案与我的模拟结果进行对比。 编辑：修正了我算法中的错误，更新了结果表。 背景 我一直在玩一个修改过的二十一点游戏，其中有一些来自标准规则的烦人的规则调整。 我已经制定了与
I have a large class with lots of methods and it's starting to get a bit unorganized and hard to navigate. I'd like to break it up into modules, where each module is a collection of class and instance methods. Perhaps something like this: UPDATE: I've now realized that this is a pretty poor example. You probably wouldn't want to move validations or attributes out of the core
我有一个有很多方法的大班，它开始有点无组织，很难导航。 我想分解成模块，其中每个模块是类和实例方法的集合。 也许是这样的： 更新：我现在已经意识到这是一个很糟糕的例子。 您可能不希望将验证或属性移出核心类。 class Large include Validations include Attributes include BusinessLogic include Callbacks end 在阅读了耶胡达关于更好的Ruby成语的文章后，我很好奇别人是如何解决这个问题的。 这是我
I have a Rakefile that compiles the project in two ways, according to the global variable $build_type , which can be :debug or :release (the results go in separate directories): task :build => [:some_other_tasks] do end I wish to create a task that compiles the project with both configurations in turn, something like this: task :build_all do [ :debug, :release ].each do |t| $build_typ
我有一个根据全局变量$build_type编译项目的$build_type ，它可以是:debug或:release （结果放在不同的目录中）： task :build => [:some_other_tasks] do end 我希望创建一个能够依次用两种配置编译项目的任务，如下所示： task :build_all do [ :debug, :release ].each do |t| $build_type = t # call task :build with all the tasks it depends on (?) end end 有没有办法像调用方法一样调用任务？ 或
Is there a way to pass named arguments to a Rake task without using environment variables? I am aware that Rake tasks can accept arguments in two formats: Environment Variables $ rake my_task foo=bar This creates an environment variable with the name foo and the value bar that can be accessed in the Rake task my_task by ENV['foo'] . Rake Task Arguments $ rake my_task['foo','bar']
有没有办法将命名参数传递给Rake任务而不使用环境变量？ 我知道Rake任务可以接受两种格式的参数： 环境变量 $ rake my_task foo=bar 这将创建一个名为foo的环境变量以及可通过ENV['foo']在Rake任务my_task访问的值bar 。 Rake任务参数 $ rake my_task['foo','bar'] 这将值foo和bar传递给前两个任务参数（如果已定义）。 如果my_task被定义为： task :my_task, :argument_1, :argument_2 那么argument_1将具
I've been reading Sandi Metz's Practical Object-Oriented Design in Ruby and many sites online discussing design in Ruby. Something I've had a hard time fully understanding is the proper way to implement dependency injection. The internet is flooded with blog posts that explain how dependency injection works in what I think is a very partial way. I understand that this is supposed
我一直在阅读Ruby中Sandi Metz的实用面向对象设计和许多网站在线讨论Ruby中的设计。 我很难完全理解的东西是实现依赖注入的正确方法。 互联网充斥着博客文章，解释依赖注入是如何工作的，我认为这是一种非常偏袒的方式。 我知道这应该是不好的： class ThisClass def initialize @another_class = AnotherClass.new end end 虽然这是一个解决方案： class ThisClass def initialize(another_class) @anothe
Most questions regarding this problem are due to missing Xcode; I have Xcode 4.2 installed. Install attempt: rvm install 1.9.3 Installing Ruby from source to: /Users/jamie/.rvm/rubies/ruby-1.9.3-p0, this may take a while depending on your cpu(s)... ruby-1.9.3-p0 - #fetching ruby-1.9.3-p0 - #extracted to /Users/jamie/.rvm/src/ruby-1.9.3-p0 (already extracted) Fetching yaml-0.1.4.tar.gz to /U
关于这个问题的大部分问题是由于缺少Xcode; 我安装了Xcode 4.2。 安装尝试： rvm install 1.9.3 Installing Ruby from source to: /Users/jamie/.rvm/rubies/ruby-1.9.3-p0, this may take a while depending on your cpu(s)... ruby-1.9.3-p0 - #fetching ruby-1.9.3-p0 - #extracted to /Users/jamie/.rvm/src/ruby-1.9.3-p0 (already extracted) Fetching yaml-0.1.4.tar.gz to /Users/jamie/.rvm/archives Extracting y
In C and many other languages, there is a continue keyword that, when used inside of a loop, jumps to the next iteration of the loop. Is there any equivalent of this continue keyword in Ruby? Yes, it's called next . for i in 0..5 if i < 2 next end puts "Value of local variable is #{i}" end This outputs the following: Value of local variable is 2 Value of local variable
在C和许多其他语言中，有一个continue关键字，当在循环内部使用时，跳转到循环的下一个迭代。 Ruby中是否有这个continue关键字的等价物？ 是的，它被称为next 。 for i in 0..5 if i < 2 next end puts "Value of local variable is #{i}" end 这输出以下内容： Value of local variable is 2 Value of local variable is 3 Value of local variable is 4 Value of local variable is 5 => 0..5 nex
I know how to catch the exceptions but what we do is to put "rescue" after a suspicious section of a code. what if you had a lot functions sending a query to mysql through mysql2 gem and you want to catch their exceptions. One thing you can do is to put a "rescue" statement in each of them. but i want to do that just by one rescue statement. So I put a "rescue" i
我知道如何捕捉异常，但我们所做的是在代码的可疑部分之后放置“救援”。 如果你有很多函数通过mysql2 gem发送一个查询到mysql并且你想要捕获它们的异常。 你可以做的一件事就是在他们每个人中加上一个“救援”声明。 但我只想通过一个救援声明来做到这一点。 因此，我在代码结束时加入了一个“救援”，并将所有代码放在“开始”和“结束”中，但它不起作用。 这里是我的代码，正如你看到的那样，在mysql查询中有一个问题，并且仅仅