How to upload csv file using django project

I am trying to create a file upload in django. inventory.html: I have two buttons download_inventory button download a csv file. I am trying to upload a file using upload_inventory button. <form method="POST" action="{% url 'bulkInventory' %}"> {% csrf_token %} <div class="panel-body"> <div class="pad-btm form-inline"> <div class=

如何使用django项目上传csv文件

我正尝试在django中创建文件上传。 inventory.html: 我有两个按钮download_inventory按钮下载一个CSV文件。 我正尝试使用upload_inventory按钮上传文件。 <form method="POST" action="{% url 'bulkInventory' %}"> {% csrf_token %} <div class="panel-body"> <div class="pad-btm form-inline"> <div class="row"> <div class=

Upgrade Django and NoReverseMatch password Error

I am trying upgrade old version Django 1.5 to newer. And after upgrade when I go to password reset page, Django give me Error: TypeError at /accounts/password/reset/ password_reset() got an unexpected keyword argument 'post_change_redirect' Request Method: GET TypeErrorRequest URL: http://localhost:8000/accounts/password/reset/ Django Version: 1.6.11 Exception Type: TypeError Excep

升级Django和NoReverseMatch密码错误

我正在尝试将旧版本的Django 1.5升级到更新版本。 升级后,当我去密码重置页面,Django给我错误: TypeError at / accounts / password / reset / password_reset()得到了一个意外的关键字参数'post_change_redirect' 请求方法:GET TypeErrorRequest URL:http:// localhost:8000 / accounts / password / reset / Django版本:1.6.11异常类型:TypeError异常值: password_reseteset()得到了一个意外的

Django Exception DoesNotExist

I have a model that has Django's model fields AND python properties at the same time. Ex: Edit2: Updated with actual models (sorry for the portuguese names) #On Produto.models.py from django.db import models from django.forms import ModelForm from openshift.models import AbstractModel from openshift.produto.models import app_name class Produto(models.Model): class

Django异常DoesNotExist

我有一个模型同时具有Django的模型字段和python属性。 例如: 编辑2:更新与实际模型(对于葡萄牙的名字抱歉) #On Produto.models.py from django.db import models from django.forms import ModelForm from openshift.models import AbstractModel from openshift.produto.models import app_name class Produto(models.Model): class Meta: app_label = app_name descricao = mod

'long' object has no attribute 'fetchall'

I don't know what is wrong in this code; previously it was working fine but after a database migration (sqlite3 to MySQL) it is no longer working. (I am using MySQL). Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 111. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/djang

'长'对象没有属性'fetchall'

我不知道这段代码有什么问题; 以前它工作正常,但在数据库迁移(sqlite3到MySQL)后,它不再有效。 (我正在使用MySQL)。 Traceback:在get_response 111中的文件“/usr/lib/python2.6/site-packages/django/core/handlers/base.py”。response = callback(request,* callback_args,** callback_kwargs)File“/ usr / lib /python2.6/site-packages/django/contrib/auth/decorators.py“在_wrapped_view中23. return view_f

Python basemap stereographic map

I want to display some values on a stereographic map (in this case southpole ( spstere )). If I display them on a cylindric map ( cyl ) everything is fine: m = Basemap(projection='cyl',llcrnrlon=-180,llcrnrlat=-90,urcrnrlon=180,urcrnrlat=90,resolution='i') CS = m.scatter(lon2,lat2,c=BT2,edgecolors='none',s=sz,cmap='gray') Now I want the same values on the southpole stereographic map, but I ca

Python底图立体图

我想在立体地图上显示一些值(在本例中为南极( spstere ))。 如果我在圆柱形地图( cyl )上显示它们,一切都很好: m = Basemap(projection='cyl',llcrnrlon=-180,llcrnrlat=-90,urcrnrlon=180,urcrnrlat=90,resolution='i') CS = m.scatter(lon2,lat2,c=BT2,edgecolors='none',s=sz,cmap='gray') 现在我想要在南极立体地图上得到相同的值,但是我不能让它起作用: m = Basemap(projection='spstere',boundinglat=-10,lo

Get artist from spotify api using ClientID

I was using spotify api to get info about a artist with the code below: spotify_artist = requests.get('https://api.spotify.com/v1/search?q=U2"&type=artist").json() print(spotify_artist['artists']['items'][0]['genres']) But I get: { "error": { "status": 401, "message": "No token provided" } } So I get a spotify clientID but when I use it its not working: https://api.spotify.co

使用ClientID从spotify API获取艺术家

我使用spotify api来获取关于艺术家的信息,代码如下: spotify_artist = requests.get('https://api.spotify.com/v1/search?q=U2"&type=artist").json() print(spotify_artist['artists']['items'][0]['genres']) 但我得到: { "error": { "status": 401, "message": "No token provided" } } 所以我得到一个Spotify客户端ID,但是当我使用它时它不工作: https://api.spotify.com/v1/search?q=U2%22&t

Why can I pass an instance method to multiprocessing.Process, but not a multiprocessing.Pool?

I am trying to write an application that applies a function concurrently with a multiprocessing.Pool . I would like this function to be an instance method (so I can define it differently in different subclasses). This doesn't seem to be possible; as I have learned elsewhere, apparently bound methods can't be pickled. So why does starting a multiprocessing.Process with a bound method a

为什么我可以将实例方法传递给multiprocessing.Process,而不是multiprocessing.Pool?

我正在尝试编写一个应用程序,该应用程序与multiprocessing.Pool同时应用一个函数。 我想这个函数是一个实例方法(所以我可以在不同的子类中定义它)。 这似乎不可能; 正如我在其他地方所了解到的,显然绑定的方法不能被腌制。 那么为什么要开始一个multiprocessing.Process 。一个绑定方法作为一个目标工作的过程? 以下代码: import multiprocessing def test1(): print "Hello, world 1" def increment(x): r

Python execute subprocess.call inside map

Hi I have the following code: import sys import multiprocessing as mp def create_parser(): from argparse import ArgumentParser, FileType ap = ArgumentParser() ap.add_argument('infile', type=FileType('r'), help="file with shell commands to execute") ap.add_argument('-n', '--ncpu', type=int, default=0, help="Number of CPUs to use (default: %(default)s: all CPU

Python在map中执行subprocess.call

嗨,我有以下代码: import sys import multiprocessing as mp def create_parser(): from argparse import ArgumentParser, FileType ap = ArgumentParser() ap.add_argument('infile', type=FileType('r'), help="file with shell commands to execute") ap.add_argument('-n', '--ncpu', type=int, default=0, help="Number of CPUs to use (default: %(default)s: all CPUs)") re

Creating network with networkx / plotly from a pandas dataframe

I'd trying to build a network from a pandas dataframe with four columns that look like this: PTDID | PBDID | BTDID | BDDID PTD000000 | PBD000024 | BTD000264 | BDD000288 PTD000001 | PBD000025 | BTD000264 | BDD000289 PTD000001 | PBD000025 | BTD000264 | BDD000290 PTD000001 | PBD000025 | BTD000264 | BDD000291 PTD000001 | PBD000025 | BTD000264 | BDD000292 PTD000000

使用networkx / plotly从熊猫数据框创建网络

我试图用一个熊猫数据框来构建一个网络,它有四列,如下所示: PTDID | PBDID | BTDID | BDDID PTD000000 | PBD000024 | BTD000264 | BDD000288 PTD000001 | PBD000025 | BTD000264 | BDD000289 PTD000001 | PBD000025 | BTD000264 | BDD000290 PTD000001 | PBD000025 | BTD000264 | BDD000291 PTD000001 | PBD000025 | BTD000264 | BDD000292 PTD000000 | PBD000024 | BTD000264 | BDD00029

Importerror: cannot import name Split

I am very new to python and need some help here. I think it comes from PATH,but I have no clue about fixing it. Please help. Once I type in import split and it keeps popping up runfile('/Users/zhihaowang/Desktop/untitled1.py', wdir='/Users/zhihaowang/Desktop') Traceback (most recent call last): File "", line 1, in runfile('/Users/zhihaowang/Desktop/untitled1.

导入器错误:无法导入名称Split

我对Python非常陌生,在这里需要一些帮助。 我认为它来自PATH,但我无法解决它。 请帮忙。 一旦我输入进口拆分,它会不断弹出 runfile('/ Users / zhihaowang / Desktop / untitled1.py',wdir ='/ Users / zhihaowang / Desktop')Traceback(最近一次调用最后一次): 在runfile('/ Users / zhihaowang / Desktop / untitled1.py',wdir ='/ Users / zhihaowang / Desktop')中的文