I am trying to grab the headers in selenium webdriver. Something similar to the following: >>> import requests >>> res=requests.get('http://google.com') >>> print res.headers I need to use the Chrome webdriver because it supports flash and some other things that I need to test a web page. Here is what I have so far in Selenium: from selenium import webdriver driver
我试图抓住硒webdriver头。 类似于以下内容： >>> import requests >>> res=requests.get('http://google.com') >>> print res.headers 我需要使用Chrome程序，因为它支持Flash和其他一些我需要测试网页的东西。 这是我迄今为止在硒中所做的： from selenium import webdriver driver = webdriver.Chrome() driver.get('https://login.comcast.net/login?r=comcast.net&s=oauth&continue
What I want to accomplish is to generate a link to view the file (ex.image or pdf). The item is not accessible by URL (https://[bucket].s3.amazonaws.com/img_name.jpg), I think because its private and not public? (I'm not the owner of the bucket, but he gave me the access_key and secret_key?) For now, all I can do is to download a file with this code. s3.Bucket('mybucket').download_file('
我想要完成的是生成一个链接来查看文件（ex.image或pdf）。 该项无法通过URL访问（https：// [bucket] .s3.amazonaws.com / img_name.jpg），我认为是因为它的私密性而非公开性？ （我不是水桶的主人，但他给了我access_key和secret_key？） 目前，我所能做的就是使用此代码下载文件。 s3.Bucket('mybucket').download_file('upload/nocturnes.png', 'dropzone/static/pdf/download_nocturnes.png') 我想在S3上访问一个图
I have a bucket called 'ben-bucket' inside that bucket I have multiple files. I want to be able to set permissions for each file URL. I'm not too sure but I'm assuming if I wanted URL for each file inside a bucket. My URL would be like this? https://ben-bucket.s3.amazonaws.com/<file_name> So basically, I want to set a public access to that URL. How would I do it? I tr
我在桶里面有一个叫做'笨桶'的桶，我有多个文件。 我希望能够为每个文件的URL设置权限。 我不太确定，但我假设我是否需要一个存储桶中的每个文件的URL。 我的网址会是这样吗？ https://ben-bucket.s3.amazonaws.com/<file_name> 所以基本上，我想设置一个公共访问该URL。 我会怎么做？ 我试过这个，它不起作用 bucket = s3.Bucket('ben-bucket').Object('db.sqlite') bucket.BucketAcl('public-rea
I've been trying to make a grid of subplots with custom size with Plotly(version 1.12.9) in Jupyter notebook(offline). There is nice examples in the Plotly website but all of them are with scattered plots. I modified one of them to make it look like the one I want to and it works with scatter plots: import plotly import plotly.offline as py import plotly.graph_objs as go py.init_notebook_m
我一直试图在Jupyter笔记本（离线）中用Plotly（版本1.12.9）制作自定义尺寸的子图。 在Plotly网站上有很好的例子，但所有这些都是分散的情节。 我修改了其中一个，使其看起来像我想要的那个，它可以与散点图一起工作： import plotly import plotly.offline as py import plotly.graph_objs as go py.init_notebook_mode(connected=True) labels = ['Oxygen','Hydrogen','Carbon_Dioxide','Nitrogen'] values = [4500,2500,1
From the documentation, "the first running vertically downwards across rows (axis 0), and the second running horizontally across columns (axis 1)" And the code is df1 = pd.DataFrame({"x":[1, 2, 3, 4, 5], "y":[3, 4, 5, 6, 7]}, index=['a', 'b', 'c', 'd', 'e']) df2 = pd.DataFrame({"y":[1, 3, 5, 7, 9], "z":[9, 8, 7, 6, 5]},
从文档中，“第一个垂直向下横跨行（轴0），第二个水平横跨列（轴1）”并且代码是 df1 = pd.DataFrame({"x":[1, 2, 3, 4, 5], "y":[3, 4, 5, 6, 7]}, index=['a', 'b', 'c', 'd', 'e']) df2 = pd.DataFrame({"y":[1, 3, 5, 7, 9], "z":[9, 8, 7, 6, 5]}, index=['b', 'c', 'd', 'e', 'f']) pd.concat([df1, df2], join='inner') # by defaul
I am trying to install "pulp" module in Anaconda Navigator's Environment tabs. But when I search in "All" packages I can't find it. It happened with other packages too. Is there any way to install my package to the desired environment? I tried to install it by opening a terminal in the environment, but I see that afterwards it won't show up in the list. Wha
我试图在Anaconda Navigator的Environment选项卡中安装“pulp”模块。 但是当我搜索“所有”包时，我无法找到它。 它也发生在其他软件包上。 有没有办法将我的软件包安装到所需的环境中？ 我试图通过在环境中打开一个终端来安装它，但是我看到之后它不会显示在列表中。 我在这里错过了什么？ 点击从环境Open terminal 在终端模式下执行conda install keras 从这里下载包装的tar.gz文件（在你的情况下，纸浆），并按照这
Is there a good way to check a form input using regex to make sure it is a proper style email address? Been searching since last night and everybody that has answered peoples questions regarding this topic also seems to have problems with it if it is a subdomained email address. There is no point. Even if you can verify that the email address is syntactically valid, you'll still need to c
有没有一种好的方法来检查表单输入使用正则表达式，以确保它是一个适当的风格电子邮件地址？ 从昨晚开始搜索，每个已经回答了人们关于这个主题的问题的人，如果它是一个subdomained的电子邮件地址，似乎也有问题。 无关紧要。 即使您可以验证电子邮件地址在语法上是否有效，您仍然需要检查它是否错误输入，并确实发送给您认为它的人。 要做到这一点的唯一方法是给他们发送一封电子邮件，让他们点击链接进行验证。 因此，
I want to use MuJoCo (http://www.mujoco.org/), an advanced physics simulator with python bindings (https://github.com/openai/mujoco-py). I've got my MuJoCo license file mjkey.text and added the required paths MUJOCO_PY_MJKEY_PATH, MUJOCO_PY_MJPRO_PATH to the environment variables accordingly. MUJOCO_PY_MJPRO_PATH = C:DropboxPhDMuJoComjpro131 MUJOCO_PY_MJKEY_PATH = C:DropboxPhDMuJoComjpro13
我想使用MuJoCo（http://www.mujoco.org/），一个使用python绑定的高级物理模拟器（https://github.com/openai/mujoco-py）。 我有我的MuJoCo许可证文件mjkey.text，并相应地将所需的路径MUJOCO_PY_MJKEY_PATH，MUJOCO_PY_MJPRO_PATH添加到环境变量中。 MUJOCO_PY_MJPRO_PATH = C:DropboxPhDMuJoComjpro131 MUJOCO_PY_MJKEY_PATH = C:DropboxPhDMuJoComjpro131bin 但是，只要我想用下面的简单代码导入libray， import mujoco
I'm writing a registration form that only needs to accept the local component of a desired email address. The domain component is fixed to the site. I am attempting to validate it by selectively copying from validators.validate_email which Django provides for EmailField : email_re = re.compile( r"(^[-!#$%&'*+/=?^_`{}|~0-9A-Z]+(.[-!#$%&'*+/=?^_`{}|~0-9A-Z]+)*" # dot-atom #
我正在写一个注册表单，只需要接受所需电子邮件地址的本地组件。 域组件固定在该站点上。 我试图通过有选择性地复制Django为EmailField提供的validators.validate_email来验证它： email_re = re.compile( r"(^[-!#$%&'*+/=?^_`{}|~0-9A-Z]+(.[-!#$%&'*+/=?^_`{}|~0-9A-Z]+)*" # dot-atom # quoted-string, see also http://tools.ietf.org/html/rfc2822#section-3.2.5 r'|^"([01-10131416-37!#-[]-177]|
I want to make multiple internal REST API call from my Django TemplateView, using requests library. Now I want to pass the session too from template view to api call. What is the recommended way to do that, keeping performance in mind. Right now, I'm extracting cookie from the current request object in template view, and passing that to requests.get() or requests.post() call. But problem
我想从我的Django TemplateView使用请求库进行多个内部REST API调用。 现在我想将模板视图中的会话也传递给api调用。 建议如何做到这一点，牢记性能。 现在，我从模板视图中的当前request对象中提取cookie ，并将其传递给requests.get()或requests.post()调用。 但问题是，我将不得不将request对象传递给我不想要的API客户端。 这是我用来传递请求的当前包装器： def wrap_internal_api_call(request, requests_api, uri,