I would like to create a secondary windows for the user's settings, so in my class QMainWindow, I call an object Settings like this: self.settingsAction = QtGui.QAction('Préférences', self) self.settingsAction.triggered.connect(lambda: Settings(self)) Then, I build my Settings class: class Settings(): """ Méthode pour effectuer les réglages du programme par l'utilisateur """
我想为用户的设置创建一个辅助窗口，所以在我的类QMainWindow中，我调用了一个像这样的对象设置： self.settingsAction = QtGui.QAction('Préférences', self) self.settingsAction.triggered.connect(lambda: Settings(self)) 然后，我建立我的设置类： class Settings(): """ Méthode pour effectuer les réglages du programme par l'utilisateur """ def __init__(self, parent): #TODO: faire de
I have a QMainWindow that launches a QDialog everytime I click on a button and I can't figure out why the python binary crashes when I close the QMainWindow while one or more dialogs are open. It's not a complex Qt app and I'm really struggling trying to understand what happens. Here's the code: # dependency modules from PyQt4 import QtGui import sys # custom modules from ui
我有一个QMainWindow，每次点击一个按钮时都会启动一个QDialog，我无法弄清楚为什么在一个或多个对话框打开时关闭QMainWindow时python二进制文件崩溃。 这不是一个复杂的Qt应用程序，我真的很努力去理解发生了什么。 代码如下： # dependency modules from PyQt4 import QtGui import sys # custom modules from ui import SingleOrderUI, DashBoardUI class SingleOrder(QtGui.QDialog, SingleOrderUI.Ui_SingleOrder):
Using Python and Splinter, currently, I need to define exactly what text, option1 to click on when an option is found on a page: from splinter import Browser browser = Browser('chrome') browser.find_option_by_text(option1).first.click() But if the option1 is not there, how can I fall back and choose any next option available rather than having to define it? And is it possible to just find an
使用Python和Splinter，目前，我需要准确定义在页面上找到选项时要点击哪些文本， option1 ： from splinter import Browser browser = Browser('chrome') browser.find_option_by_text(option1).first.click() 但是，如果option1不在那里，我该如何回退并选择下一个可用选项，而不必定义它？ 是否有可能在页面上找到一个选项，并选择遇到的任何第一个可用选项，而无需定义该选项？ 预先感谢您，并一定会upvote /接受答案
I am trying to produce a signature for the Amazon Product Advertising API, been at it a few hours and am still getting a 403 - could anyone have a quick look at the code and tell me if I am doing anything wrong please? This is the function I use to create the signature def create_signature(service, operation, version, search_index, keywords, associate_tag, time_stamp, access_key): start_string
我试图为亚马逊产品广告API制作一个签名，并在几个小时后仍然收到403 - 任何人都可以快速查看代码并告诉我我是否做错了？ 这是我用来创建签名的功能 def create_signature(service, operation, version, search_index, keywords, associate_tag, time_stamp, access_key): start_string = "GETn" + "webservices.amazon.comn" + "/onca/xmln" + "AWSAccessKeyId=" + access_
So I'm attempting to collect reviews from Amazon using their API. Unfortunately though it seems that I might be doing something wrong at some point in my program. It's sending back a response that many others were apparently getting. Believe me, I've gone through and looked and everyone elses questions and nothing has worked. Please help me. Here's the code: __author__ = 'd
所以我试图从他们的API中收集来自亚马逊的评论。 不幸的是，尽管我的程序在某些时候可能会做错某些事情。 它发回了许多其他人显然获得的回应。 相信我，我已经经历过，看起来，每个人都隐藏问题，没有任何工作。 请帮帮我。 代码如下： __author__ = 'dperkins' import requests import amazonproduct import time import datetime import hmac import hashlib import base64 import urllib import ssl from bs4 import B
Recently I have been learning about managed attributes in Python and a common theme with properties and descriptors is, that they have to be assigned as class attributes. But nowhere can I find an explanation of why and especially why they cannot be assigned as instance attributes. So my question has actually two parts: why do properties / descriptor instances have to be class attributes? w
最近我一直在学习Python中的托管属性，并且使用属性和描述符的常见主题是，它们必须被分配为类属性。 但我无处可以找到解释为什么，特别是为什么他们不能被指定为实例属性。 所以我的问题实际上有两个部分： 为什么属性/描述符实例必须是类属性？ 为什么属性/描述符实例不能成为实例属性？ 这是因为Python尝试解析属性的方式： 首先它会检查它是否在课堂级定义 如果是，它会检查它是属性还是数据描述符 如果是的话
I used icontains for filtering data which equivalents to 'LIKE'. But it won't trigger filter for strings with other ASCII characters eg / , ' , & , etc. Here's a sample code Chartofaccount.objects.all().filter(title__icontains=search).filter(isdeleted=0).order_by('-pk') which works perfectly well when searching. But when I search for words like cats & dogs It
我使用了图标来过滤与“LIKE”等价的数据。 但它不会触发其他ASCII字符的字符串过滤器，例如/，'，＆等。 这是一个示例代码 Chartofaccount.objects.all().filter(title__icontains=search).filter(isdeleted=0).order_by('-pk') 这在搜索时效果很好。 但是当我搜索像 cats & dogs 它不会返回任何结果，与其他陈述的字符相同。
I am a newbie in Python and Django Development, I learned a lot from the easy read examples provided by the community. But recently I want to implement a customized admin filter for the admin console shipped with Django. I searched a lot and only found some out-of-date approaches to get it done. Such as: Custom Filter in Django Admin on Django 1.3 or below I tried to read the source code for
我是Python和Django开发的新手，我从社区提供的简单阅读示例中学到了很多东西。 但是最近我想为Django自带的管理控制台实现一个自定义的管理过滤器。 我搜索了很多，只找到了一些过时的方法来完成它。 如：在Django 1.3或更低版本的Django Admin中自定义过滤器 我试图在'django.contrib.admin'应用程序中阅读过滤器模块的源代码，但不幸的是我很难理解代码背后的基本原理。 所以我想知道是否有人可以提供一些例子
I'm trying to create a Flask app (Postgresql database) that shows the latest score from individual players, including the average scores and goals for the team. So a player can have multiple scores, but on the leaderboard I only want to show her most recent score, and show an average number of goals for the whole team, based on the latest score per player. My Models.py class Player(db.Mod
我正在尝试创建一个Flask应用程序（Postgresql数据库），显示各个玩家的最新成绩，包括团队的平均得分和目标。 所以玩家可以有多个分数，但是在排行榜上，我只想显示她最近的分数，并根据每个玩家的最新分数显示整个团队的平均目标数。 我的Models.py class Player(db.Model): __tablename__ = 'player' id = db.Column(db.Integer, primary_key=True) firstname = db.Column(db.String, nullable=False) sco
The results of an ORM query (eg, MyObject.query()) need to be ordered according to a ranking algorithm that is based on values not within the database (ie from a separate search engine). This means 'order_by' will not work, since it only operates on fields within the database. But, I don't want to convert the query results to a list, then reorder, because I want to maintain the abi
ORM查询（例如MyObject.query（））的结果需要根据基于不在数据库内的值的排序算法（即从单独的搜索引擎）进行排序。 这意味着'order_by'将不起作用，因为它只对数据库中的字段进行操作。 但是，我不想将查询结果转换为列表，然后重新排序，因为我想保持向查询添加更多约束的能力。 例如： results = MyObject.query() results = my_reorder(results) results = results.filter(some_constraint) 这可能通过SQLAlc