My camera calibration and distortion matrixes, obtained from aruco_calibration_fromimages.exe : [[3.19439125e+03 0.00000000e+00 1.98509417e+03] [0.00000000e+00 3.20213561e+03 1.55099552e+03] [0.00000000e+00 0.00000000e+00 1.00000000e+00]] [[0.1395281 -0.38313647 0.00505558 0.00237535 0.33952515]] Image, where I try to detect: aruco_simple.exe succeeds But python c
我的相机校准和失真矩阵，从aruco_calibration_fromimages.exe获得： [[3.19439125e+03 0.00000000e+00 1.98509417e+03] [0.00000000e+00 3.20213561e+03 1.55099552e+03] [0.00000000e+00 0.00000000e+00 1.00000000e+00]] [[0.1395281 -0.38313647 0.00505558 0.00237535 0.33952515]] 图片，我尝试检测的地方： aruco_simple.exe成功 但是Python代码无法找到任何东西： fs = cv2.FileStorag
Lets say I have something like this - class A(object): c = C() class B(A): pass class C(object): def __init__(self): pass def get_parent_class(self): # This should return B How would I implement get_parent_class , so that it will work as following - B.c.get_parent_class() # Returns the class type B (not the instance b!) Is this even possible? I basically h
可以说我有这样的事情 - class A(object): c = C() class B(A): pass class C(object): def __init__(self): pass def get_parent_class(self): # This should return B 我将如何实现get_parent_class ，以便它能够如下工作 - B.c.get_parent_class() # Returns the class type B (not the instance b!) 这甚至有可能吗？ 我基本上有一个父类（在我们的例子中是类A ），它包含一个变
How can I get a model name as a "string" from a model instance. I know you can do something like type(model_instance) but this is returning the class itself as an object <Model_Name: > not as a string. from user.models import User user = User.objects.create_user(tel='1234567890', password='YKH0000000') print(user._meta.model) <class 'user.models.User'> print(user._meta.mod
我如何从模型实例中获取模型名称作为“字符串”。 我知道你可以做类似type(model_instance)事情，但是type(model_instance)类本身作为<Model_Name: >而不是字符串返回。 from user.models import User user = User.objects.create_user(tel='1234567890', password='YKH0000000') print(user._meta.model) <class 'user.models.User'> print(user._meta.model.__name__) User print(user.__class__.__name__) User 通
This question already has an answer here: Python - Access class variable from instance 2 answers You can make use of self keyword in python instead of using the current class name. class MyLongAdvancedClassName: ... _template = " My long advanced text %i " def method(self): print self._template Hope it helps. Probably what you are looking for is to use self (look at S
这个问题在这里已经有了答案： Python - 从实例2的答案访问类变量 你可以在python中使用self关键字而不是使用当前的类名。 class MyLongAdvancedClassName: ... _template = " My long advanced text %i " def method(self): print self._template 希望能帮助到你。 可能你正在寻找的是使用自我（看San的答案）。 但是这需要你有一个类的实例。 如果你想用类自己做，那么你可以使用classmethod
I am new to classes and writing one to perform a tracking and timing task. Have looked at this but still having trouble getting one aspect of the functionality to work. Here's the part of what I've got to demonstrate the problem: class seperate_trackers(): def __init__(self): print ("class initiated") def print_instance_name(self): print (self.__class__.__na
我是新来的班级和写一个执行跟踪和时间任务。 已经看过这个，但仍然有困难让功能的一个方面工作。 以下是我必须证明问题的部分： class seperate_trackers(): def __init__(self): print ("class initiated") def print_instance_name(self): print (self.__class__.__name__) 创建它的一个实例： track_task1 = separate_trackers() >> class initiated 在那里运行该方法： track_task
I create a named tuple like this: from collections import namedtuple spam = namedtuple('eggs', 'x, y, z') ham = spam(1,2,3) Then I can access elements of ham with eg >>> ham.x 1 >>> ham.z 3 In the interpreter, >>> ham eggs(x=1, y=2, z=3) But what if I just want to get 'eggs'? The only way I've been able to think of is >>> ham.__repr__.split(
我创建一个像这样的命名元组： from collections import namedtuple spam = namedtuple('eggs', 'x, y, z') ham = spam(1,2,3) 然后，我可以访问例如火腿的元素 >>> ham.x 1 >>> ham.z 3 在翻译中， >>> ham eggs(x=1, y=2, z=3) 但是如果我只想得到'鸡蛋'呢？ 我能想到的唯一方法就是 >>> ham.__repr__.split('(')[0] 'eggs' 但这似乎有点混乱。 有没有更干净的方法呢？
Let's consider python (3.x) scripts: main.py: from test.team import team from test.user import user if __name__ == '__main__': u = user() t = team() u.setTeam(t) t.setLeader(u) test/user.py: from test.team import team class user: def setTeam(self, t): if issubclass(t, team.__class__): self.team = t test/team.py: from test.user import user clas
让我们考虑python（3.x）脚本： main.py： from test.team import team from test.user import user if __name__ == '__main__': u = user() t = team() u.setTeam(t) t.setLeader(u) 测试/ user.py： from test.team import team class user: def setTeam(self, t): if issubclass(t, team.__class__): self.team = t 测试/ team.py： from test.user import user class team
How do I get the name of the class I am currently in? Example: def get_input(class_name): [do things] return class_name_result class foo(): input = get_input([class name goes here]) Due to the nature of the program I am interfacing with (vistrails), I cannot use __init__() to initialize input . obj.__class__.__name__ will get you any objects name, so you can do this: class Cla
我如何获得我目前所在班级的名字？ 例： def get_input(class_name): [do things] return class_name_result class foo(): input = get_input([class name goes here]) 由于程序的性质，我与（vistrails）接口，我不能使用__init__()来初始化input 。 obj.__class__.__name__将为您提供任何对象名称，因此您可以执行此操作： class Clazz(): def getName(self): return self.__class__.__name__
This question already has an answer here: Getting the class name of an instance in Python 8 answers You have a list of type objects, and both __str__ and __repr__ of type objects have a <type 'x'> form. If you want to print list of names of type objects you need to perform conversion manually: print [t.__name__ for t in values]
这个问题在这里已经有了答案： 在Python 8中获取实例的类名答案 您有一个类型对象列表，并且类型对象的__str__和__repr__都有一个<type 'x'> __repr__ <type 'x'>形式。 如果您想打印类型对象的名称列表，则需要手动执行转换： print [t.__name__ for t in values]
This question already has an answer here: Getting the class name of an instance in Python 8 answers 您可以查看实例的globals字典并查找将其自身作为值的项目。 class Foo(object): def bar(self): return [k for k,v in globals().items() if v is self] def bah(self): d = {v:k for k,v in globals().items()} return d[self] f = Foo() g = Foo() print f.bar(), g.bar() print f
这个问题在这里已经有了答案： 在Python 8中获取实例的类名答案 您可以查看实例的globals字典并查找将其自身作为值的项目。 class Foo(object): def bar(self): return [k for k,v in globals().items() if v is self] def bah(self): d = {v:k for k,v in globals().items()} return d[self] f = Foo() g = Foo() print f.bar(), g.bar() print f.bah(), g.bah() >>> ['f'] ['g