This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers You can grab the file and loop the lines to do stuff with like this: filehandle = open("Hex.txt", "r") for line in filehandle: print (line) Or just grab the whole file into a string: with open("Hex.txt", "r") as myfile: data=myfile.read() There are actually several diffe
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 你可以抓住这个文件并循环播放这些东西，像这样： filehandle = open("Hex.txt", "r") for line in filehandle: print (line) 或者把整个文件抓成一个字符串： with open("Hex.txt", "r") as myfile: data=myfile.read() 实际上有几种不同的方法可以实现这一点，这取决于您计划如何处理数据。 在StackOverflow上搜索，但这应该
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers Open the file using open() and convert into a list like so: with open("myfile.txt") as myfile: int_list = [int(l.strip()) for l in myfile] This iterates over every line, strips the n at the end, converts into an int , and puts it all into a list.
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 使用open()打开文件并将其转换为如下所示的列表： with open("myfile.txt") as myfile: int_list = [int(l.strip()) for l in myfile] 这遍历每一行，在最后剥离n ，转换为一个int ，并将其全部放入列表中。
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers When reading a file (line-by-line), usually the new line characters are appended to the end of the line, as you loop through it. If you want to get rid of them? with open('filename.txt', 'r') as f: for line in f: line = line.strip('n') #do things with the strip
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 在逐行读取文件时，通常将新行字符追加到行的末尾，就像循环它一样。 如果你想摆脱它们？ with open('filename.txt', 'r') as f: for line in f: line = line.strip('n') #do things with the stripped line! 这与（在Python中）相同： with open("file.txt", "r") as f: for line in f: line = line.rstr
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers You need to iterate through the file rather than the line: #! /usr/bin/python file = open('/home/results/err.txt') for line in file: print line file.readline() only reads the first line. When you iterate over it, you are iterating over the characters in the line. file.readl
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 您需要遍历文件而不是行： #! /usr/bin/python file = open('/home/results/err.txt') for line in file: print line file.readline()只读取第一行。 当你遍历它时，你正在迭代该行中的字符。 file.readline()已经读取一行。 迭代该行会为您提供单个字符。 相反，使用： for line in file: … 尝试这个 ： #! /usr/bin/pytho
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers This is one way to achieve that: with open('filename') as file: lines = [i.strip() for i in file] If you want your list to contain the numbers ( int ) instead of strings the following code will achieve this: with open('seq.txt') as f: numbers = [int(i) for i in f] Thanks to
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 这是实现这一目标的一种方式： with open('filename') as file: lines = [i.strip() for i in file] 如果你想让你的列表包含数字（ int ）而不是字符串，下面的代码将实现这一点： with open('seq.txt') as f: numbers = [int(i) for i in f] 感谢Ninja Puppy♦改进代码。
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers Im not sure why you used the split function. Instead i think the following list comprehension will help you. f = open('animal.txt','r') myList = [line.strip() for line in f] f.close() Hope it helps.
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 我不知道你为什么使用分割功能。 相反，我认为下面的列表理解会帮助你。 f = open('animal.txt','r') myList = [line.strip() for line in f] f.close() 希望能帮助到你。
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers import io data = [] with io.open('MasterList.txt', encoding='latin-1') as myfile: for i in myfile.readlines(): data.append(i) Then you can loop data and compare it with the entered password . You can use: if password in data: print "Password found in data"
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 import io data = [] with io.open('MasterList.txt', encoding='latin-1') as myfile: for i in myfile.readlines(): data.append(i) 然后，您可以循环data并将其与输入的password进行比较。 您可以使用： if password in data: print "Password found in data"
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers You should not be storing unencrypted login details in text files. However, here is a very simple solution anyway: f=open("/authentication/account.txt","r") lines=f.readlines() username=lines[0] password=lines[1] f.close()
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 您不应该将未加密的登录详细信息存储在文本文件中。 不过，无论如何，这是一个非常简单的解决方案： f=open("/authentication/account.txt","r") lines=f.readlines() username=lines[0] password=lines[1] f.close()
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers readlines returns a list of strings with all remaining lines in the file. As the python docs state you could also use list(inFile) to read all ines (https://docs.python.org/3.6/tutorial/inputoutput.html#methods-of-file-objects) But your problem is that python reads the line inclu
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 readlines返回文件中所有剩余行的字符串列表。 作为python文档状态，您还可以使用list(inFile)来读取所有ines（https://docs.python.org/3.6/tutorial/inputoutput.html#methods-of-file-objects） 但你的问题是，python读取包含换行符（ n ）的行。 只有最后一行在文件中没有换行符。 所以通过比较guess == real你比较'password1n
This question already has an answer here: In Python, how do I read a file line-by-line into a list? 35 answers You can use f.readlines() instead of f.read() . This function returns a list of all the lines in the file. with open("/home/tony/Downloads/page1/test.html", "r") as f: for line in f.readlines(): print(line) Alternatively you could use list(f) . f = open("/home/tony/D
这个问题在这里已经有了答案： 在Python中，如何逐行读取文件到列表中？ 35个答案 你可以使用f.readlines()而不是f.read() 。 该函数返回文件中所有行的列表。 with open("/home/tony/Downloads/page1/test.html", "r") as f: for line in f.readlines(): print(line) 或者你可以使用list(f) 。 f = open("/home/tony/Downloads/page1/test.html", "r") f_lines = list(f) for line in f_lines: print(l