I have to find the difference between the sum of 4 sub-matrices, which I get after splitting the matrix A in any way, in order to get the lowest difference between the sum of sub-matrix. For example, for a matrix A, 3 0 2 -8 -8 5 3 2 2 3 2 5 2 1 4 3 4 -1 4 2 -3 6 2 4 3 I could split it like this: 3 | 0 2 -8 -8 5 | 3 2 2 3 2 | 5 2 1
为了得到子矩阵之和的最小差值，我必须找出4个子矩阵的总和之间的差异，这是我以任何方式分割矩阵A后得到的。 例如，对于矩阵A， 3 0 2 -8 -8 5 3 2 2 3 2 5 2 1 4 3 4 -1 4 2 -3 6 2 4 3 我可以像这样拆分它： 3 | 0 2 -8 -8 5 | 3 2 2 3 2 | 5 2 1 4 ------------------- 3 4 -1 | 4 2 -3 6 2 | 4 3 每个子矩阵内的所有元素的总和给出以下结
Suppose I have a few timestamps given as integers (seconds) from the Unix Epoch (1970-01-01 00:00:00Z). How do I convert them into the proper date-time in the local timezone? I've been looking at the as.POSIXct help page as well as related questions on SO. It's easy to do in UTC, but for some reason I can't seem able to do it straightforwardly for the local timezone, or for anothe
假设我在Unix Epoch（1970-01-01 00：00：00Z）中给出了几个时间戳（整数）（秒）。 我如何将它们转换为当地时区的适当日期时间？ 我一直在寻找as.POSIXct帮助页面以及SO上的相关问题。 UTC很容易做到，但出于某种原因，我似乎无法直接为当地时区或另一个时区（顺便说一下，我恰好在“America / Los_Angeles”或“PST5PDT”中根据白天储蓄是否在指定时间生效，变成“PST或”PDT“;所以我通常指定基于位置的时区而不是”PST“或”PDT“，
I have the following scripts: library("gplots") mydata <- mtcars mydata.nr <- nrow(mydata) mydata.newval <- data.frame(row.names=rownames(mydata),new.val=-log(runif(mydata.nr))) # Functions hclustfunc <- function(x) hclust(x, method="complete") distfunc <- function(x) dist(x,method="euclidean") # Set colors hmcols <- rev(redgreen(256)); # Plot the scaled data heatmap.2(as.m
我有以下脚本： library("gplots") mydata <- mtcars mydata.nr <- nrow(mydata) mydata.newval <- data.frame(row.names=rownames(mydata),new.val=-log(runif(mydata.nr))) # Functions hclustfunc <- function(x) hclust(x, method="complete") distfunc <- function(x) dist(x,method="euclidean") # Set colors hmcols <- rev(redgreen(256)); # Plot the scaled data heatmap.2(as.matrix(mydata),d
Foremost, I am looking for a fast(er) way of subsetting/indexing a matrix many, many times over: for (i in 1:99000) { subset.data <- data[index[, i], ] } Background: I'm implementing a sequential testing procedure involving the bootstrap in R. Wanting to replicate some simulation results, I came upon this bottleneck where lots of indexing needs to be done. For implementation of the
最重要的是，我正在寻找一种快速（呃）的方式来对一个矩阵进行子集化/索引化， for (i in 1:99000) { subset.data <- data[index[, i], ] } 背景： 我正在实施一个涉及R的引导程序的顺序测试程序。为了复制一些模拟结果，我遇到了需要完成大量索引的瓶颈。 为了实现block-bootstrap，我创建了一个索引矩阵，用它对原始数据矩阵进行子集化，以绘制数据的重采样。 # The basic setup B <- 1000 # no. of bootstrap r
Warnings generated when evaluation arguments of S4 generic functions can not be caught using withCallingHandlers (). Illustration of the normal behaviour of withCallingHandlers: ### simple function that sends a warning send_warning <- function() { warning('send_warning') } send_warning() # Warning message: # In send_warning() : send_warning ### the warning can be caught by withCallingHan
使用withCallingHandlers （）无法捕获S4通用函数的评估参数时生成的警告 。 withCallingHandlers的正常行为的示例： ### simple function that sends a warning send_warning <- function() { warning('send_warning') } send_warning() # Warning message: # In send_warning() : send_warning ### the warning can be caught by withCallingHandlers withCallingHandlers(send_warning(), warning = function(w) {
I'm trying to have column headings and the horizontal line underneath the headings separated by the groups. When I do the following it works, library(Hmisc) data(mtcars) latex(mtcars, file ='', cgroup = c("Group 1", "Group 2"), n.cgroup = c(5, 6)) but when I try to remove the rownames, the line under Group 1 & 2 merge into the same line library(Hmisc) data(mtcars) latex(mtcars, file =
我正在尝试在由组分隔的标题下方添加列标题和水平线。 当我做下面的工作时， library(Hmisc) data(mtcars) latex(mtcars, file ='', cgroup = c("Group 1", "Group 2"), n.cgroup = c(5, 6)) 但是当我尝试删除rownames时，组1和2下的行合并到同一行中 library(Hmisc) data(mtcars) latex(mtcars, file ='', cgroup = c("Group 1", "Group 2"), n.cgroup = c(5, 6), rowname = NULL) 有谁知道一种方法来解决这个问题？ 当l
Under what circumstances does the readRDS() function in R try to load packages/namespaces? I was surprised to see the following in a fresh R session: > loadedNamespaces() [1] "base" "datasets" "graphics" "grDevices" "methods" "stats" [7] "tools" "utils" > x <- readRDS('../../../../data/models/my_model.rds') There were 19 warnings (use warnings() to see them) > l
R中的readRDS()函数在什么情况下尝试加载包/名称空间？ 我很惊讶在新的R会议上看到以下内容： > loadedNamespaces() [1] "base" "datasets" "graphics" "grDevices" "methods" "stats" [7] "tools" "utils" > x <- readRDS('../../../../data/models/my_model.rds') There were 19 warnings (use warnings() to see them) > loadedNamespaces() [1] "base" "class" "colorspa
This may be a simplest thing for lot of people, but I'm struggling with it. I'd like to draw a line with color using html tag "hr" This is what I have tried so far in ui.R file : HTML("<hr color='purple' >") HTML('<hr color="purple" >') hr( color="purple" ) None of them worked - any suggestions please? Shiny exposes a lot of control over the look and feel of the
对许多人来说，这可能是最简单的事情，但我正在为此付出努力。 我想使用html标签“hr”绘制颜色线这是我迄今在ui.R文件中尝试过的： HTML("<hr color='purple' >") HTML('<hr color="purple" >') hr( color="purple" ) 他们都没有工作 - 有任何建议吗？ Shiny暴露了对应用程序外观和感觉的很多控制，但碰巧hr的颜色不是其中之一。 所以你需要深入CSS来控制元素的外观。 您可以通过在Shiny中使用includeCSS来完
From meteorological data (hourly values of temperature, wind and humidity) I managed to plot time series of wind speed and direction. Now I would like to add wind vectors on the time series plot. Here you can see the output I would like (arrows drawn over the actual plot). I am using ggplot2, been looking through stackoverflow, ggplot2 package docs (will continue) but no solution found. Any
从气象数据（温度，风和湿度的小时值）我设法绘制风速和风向的时间序列。 现在我想在时间序列图上添加风向量。 在这里，您可以看到我想要的输出（箭头绘制在实际绘图上）。 我正在使用ggplot2，一直在寻找通过stackoverflow，ggplot2软件包文档（将继续），但没有找到解决方案。 任何想法或指示将看起来是一个起点。 提前致谢 编辑问题正如@slowlearner的评论中所建议的那样，我在此添加代码和数据以创建可重复的示例。
Every time I run the command fix(DT) on a data.table , after closing the fix window, DT turns into a data.frame object. Is this normal? library(data.table) DT <- data.table(a = 1:2, b = 2:3) > class(DT) [1] "data.table" "data.frame" fix(DT) # close the window > class(DT) [1] "data.frame" EDIT: some session info: R version 3.0.0 (2013-04-03) Platform: x86_64-w64-mingw32/x64 (64
每次我在data.table上运行命令fix(DT)时，在关闭修复窗口后， DT变成一个data.frame对象。 这是正常的吗？ library(data.table) DT <- data.table(a = 1:2, b = 2:3) > class(DT) [1] "data.table" "data.frame" fix(DT) # close the window > class(DT) [1] "data.frame" 编辑： 一些会话信息： R version 3.0.0 (2013-04-03) Platform: x86_64-w64-mingw32/x64 (64-bit) fix调用edit 。 但是，没有data.