I'm trying to require a config file in index.php by using: require_once __DIR__/application/common/config/Config.php; However, PHP error logs state division by zero. The full path is /var/www/application/common/config/Config.php How do I ensure this path is correctl represented in my require_once statement? 您需要使用PHP中的字符串引号... require_once __DIR__ . '/application/common/confi
我试图要求在index.php中的配置文件通过使用： require_once __DIR__/application/common/config/Config.php; 但是，PHP错误日志的状态除以零。 完整路径是/var/www/application/common/config/Config.php 如何确保这条路径在我的require_once语句中是正确的？ 您需要使用PHP中的字符串引号... require_once __DIR__ . '/application/common/config/Config.php'; require_once __DIR__ . '/application/common/config/Confi
I have a simple script to check how many files a user has uploaded: $sql = "SELECT * from $username where file IS NOT NULL"; $result = mysql_query($sql); $count=mysql_num_rows($result); If the table $username does not have any rows where file is not null it spits out: "Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in..." What can I do to avoid t
我有一个简单的脚本来检查用户上传了多少文件： $sql = "SELECT * from $username where file IS NOT NULL"; $result = mysql_query($sql); $count=mysql_num_rows($result); 如果表$用户名没有任何行，其中文件不为空它将吐出： “警告：mysql_num_rows（）：提供的参数不是有效的MySQL结果资源...” 我能做些什么来避免这种情况？ 有没有简单的方法来简单地抑制这个错误消息显示？ 还是一个简单的“if”语句，可以防止SQL
具体来说，我想创建一个Array类，并希望重载[]运算符。 If you are using PHP5 (and you should be), take a look at the SPL ArrayObject classes. The documentation isn't too good, but I think if you extend ArrayObject, you'd have your "fake" array. EDIT: Here's my quick example; I'm afraid I don't have a valuable use case though: class a extends ArrayObject { pub
具体来说，我想创建一个Array类，并希望重载[]运算符。 如果您使用PHP5（并且您应该是），请查看SPL ArrayObject类。 文档不太好，但我想如果你扩展ArrayObject，你会有你的“假”数组。 编辑：这是我的快速示例; 恐怕我没有宝贵的使用案例： class a extends ArrayObject { public function offsetSet($i, $v) { echo 'appending ' . $v; parent::offsetSet($i, $v); } } $a = new a; $a[] = 1;
I would like to show the stock status (eg. In Stock / Out of Stock) for each product variation shown in the drop down list of variations on the Woocommerce Product Page. I have copied the relevant function to my theme's functions.php file, and can edit the content, but am unsure how to pull out the required stock status for each variation. // Updated Woocommerce Product Variation Select
我想显示Woocommerce产品页面变体下拉列表中显示的每种产品变体的库存状态（例如库存/缺货）。 我已将相关函数复制到我的主题的functions.php文件中，并且可以编辑内容，但不确定如何为每个变体提取所需的库存状态。 // Updated Woocommerce Product Variation Select if ( ! function_exists( 'wc_dropdown_variation_attribute_options' ) ) { /** * Output a list of variation attributes for use in the car
This question already has an answer here: How to suppress the “Division by zero” error and set the result to null for the whole application? 4 answers This should work for you: (It's testing if $total_voting is zero and returns in this case false) function percent($liked, $total_voting) { if($total_voting == 0) return false; $liked = (int)$liked; $total_voting =
这个问题在这里已经有了答案： 如何在整个应用程序中禁止“除零除”错误并将结果设置为空？ 4个答案 这应该适合你： （它正在测试$total_voting是否为零，并且在这种情况下返回false） function percent($liked, $total_voting) { if($total_voting == 0) return false; $liked = (int)$liked; $total_voting = (int)$total_voting; return ceil(($liked/$total_voting)*100); }
I want to create a custom page for my WordPress blog that will execute my PHP code in it, whilst remaining a part of the overall site CSS/theme/design. The PHP code will make use of 3rd party APIs (so I need to include other PHP files) How do I accomplish this? NB I do not have a specific need to interact with the Wordpress API - apart from including certain other PHP libs I need I have no
我想为我的WordPress博客创建一个自定义页面，它将执行我的PHP代码，同时保留整个网站CSS /主题/设计的一部分。 PHP代码将使用第三方API（所以我需要包含其他PHP文件） 我该如何做到这一点？ NB我没有特别需要与Wordpress API进行交互 - 除了包含某些其他PHP库，我需要在我想包含在WP页面中的PHP代码中没有其他依赖项。 所以显然任何不需要学习WP API的解决方案都是最好的解决方案。 您不需要与API交互或使用插件。
I am trying to send email from the server but it's not sending it throws an error. In phpinfo() I checked mail function is enabled, what's wrong why mail is not sending if anybody has idea means please tell me, This is my code, <?php $msg = "test cotent"; $send =mail("xxxxx@gmail.com","My subject",$msg); if($send) echo 'sent!'; else echo $errorMessage = error_get_last()['message'];
我试图从服务器发送电子邮件，但它没有发送它会引发错误。 在phpinfo()我检查邮件功能启用，为什么邮件不发送，如果有人有想法意味着什么是错的请告诉我， 这是我的代码， <?php $msg = "test cotent"; $send =mail("xxxxx@gmail.com","My subject",$msg); if($send) echo 'sent!'; else echo $errorMessage = error_get_last()['message']; ?> 错误， mail(): SMTP server response: 554 5.7.1 : Relay access denie
I want to send an email with PHPMailer. The mail is a HTML made up mail with Beefree. First the whole email was a PHP variable, but then I get the email with the first part repeated. I think this is a result of having a head in the body, but I'm not sure. To clear this out the mail I want to send is this (with fancy lay-out): [image] Hello John, How are you? Best regards! But it is s
我想发送一封电子邮件给PHPMailer。 邮件是由Beefree发送的HTML邮件。 首先整个电子邮件是一个PHP变量，但随后我重复了第一部分的电子邮件。 我认为这是身体有头的结果，但我不确定。 为了解决这个问题，我想发送的邮件是这样的（花哨布局）： [image] Hello John, How are you? Best regards! 但它是这样发送的： [image] Hello $name, [image] Hello $name, <div style="Margin: 0 auto;min-width: 320px;max-wi
Please see my email sending code below and it is showing the following error while sending the email.. Unable to send email using PHP mail(). Your server might not be configured to send mail using this method. My Controller: $from_email= "******"; $to_email = 'dummy@dummy.com'; $subject='Password Reset Request'; $htmlContent = '<p>'.$link.'</p>'; $this->load->lib
请在下面看到我的电子邮件发送代码，并在发送电子邮件时显示以下错误。 无法使用PHP邮件发送电子邮件（）。 您的服务器可能未配置为使用此方法发送邮件。 我的控制器： $from_email= "******"; $to_email = 'dummy@dummy.com'; $subject='Password Reset Request'; $htmlContent = '<p>'.$link.'</p>'; $this->load->library('email'); $config['mailtype'] = 'html'; $this->em
Thanks in advance to all. I am designing a shopping cart in php and mysql. I want to send order confirmation email to the client and also to admin registered email-id. My email function is function send_mail($address,$subject,$message,$path){ global $error; $mail = new PHPMailer(); //$mail->isSMTP(); //$mail->SMTPDebug = 1; // Enable v
在此先感谢所有人。 我正在用php和mysql设计一个购物车。 我想发送订单确认电子邮件给客户，也发送给管理员注册的电子邮件ID。 我的电子邮件功能是 function send_mail($address,$subject,$message,$path){ global $error; $mail = new PHPMailer(); //$mail->isSMTP(); //$mail->SMTPDebug = 1; // Enable verbose debug output //$mail->SMTPAuth = t