I recently developed an installer for a web application (Yes, Web Application with an Installer) using Wix Tool Set. The wizard guides the user to obtain all the basic information the site need for the installation, and looks like below: Using custom actions at the end of the installation I configured dynamically the IIS to handler CGI using the documentation, to configure FastCGI to Host PHP
我最近使用Wix Tool Set为Web应用程序开发了一个安装程序（是，带有安装程序的Web应用程序）。 该向导指导用户获取网站安装所需的所有基本信息，如下所示： 在安装结束时使用自定义操作，我使用文档动态地配置IIS以处理CGI，以将FastCGI配置为托管PHP，Python， 应用程序 。 实现这些结果有很多步骤和发展，但问题在于： 我安装了应用程序，一切正常，但是，如果我卸载或安装另一个实例或另一个WebApplication，由IIS配置
This question already has an answer here: Parsing values from a JSON file? 7 answers Try this : $response=json_decode($json,true); echo $amount=$response['Body']['stkCallback']['CallbackMetadata']['Item']['0']['Value']; echo $TransactionDate=$response['Body']['stkCallback']['CallbackMetadata']['Item']['1']['Value']; echo $PhoneNumber=$response['Body']['stkCallback']['CallbackMetadata']['It
这个问题在这里已经有了答案： 从JSON文件解析值？ 7个答案 尝试这个 ： $response=json_decode($json,true); echo $amount=$response['Body']['stkCallback']['CallbackMetadata']['Item']['0']['Value']; echo $TransactionDate=$response['Body']['stkCallback']['CallbackMetadata']['Item']['1']['Value']; echo $PhoneNumber=$response['Body']['stkCallback']['CallbackMetadata']['Item']['2']['Value']; 你现在
I have a php login, the user puts in a username/password, it checks the mysql db against the login information. If authenticated a session is created via php and the user can now access the system with the php session. My question is once they authenticate via php/session what would be the process to authorize the user to see if they have the right login permissions to access a nodejs server wi
我有一个php登录，用户放入一个用户名/密码，它检查登录信息的MySQL数据库。 如果通过身份验证会话是通过PHP创建的，用户现在可以通过php会话访问系统。 我的问题是，一旦他们通过PHP /会话进行身份验证，将授权用户查看他们是否拥有正确的登录权限以使用socket.io访问nodejs服务器的过程是什么？ 我不想让这个人有权访问nodejs / socket.io函数/服务器，除非他们通过php登录进行了身份验证。 更新 要求： 首先运行redi
I have tried lots of things and could not get through yet. I have a json string with some single quotes, double quotes and some other characters which are causing an error when I am trying to iterate the json by converting in into an array. The quotes are escapes using addslashes and are going correctly in the database. But when I am converting the string to array using json_decode and strips
我已经尝试了很多东西，但还没有完成。 我有一个单引号，双引号和其他字符的json字符串，当我尝试通过转换为数组来迭代json时导致错误。 引号是使用addslashes的转义，并在数据库中正确执行。 但是当我使用json_decode和stripslashes将字符串转换为数组时，它会将无效参数传递给for循环。 请建议。 提前致谢。 在报价单上做这件事： $str = htmlentities($str, ENT_QUOTES); 他们会按照你的方式起飞。 正如我记得
{"": "attachment-2","": "attachment-1"} I am getting this JSON-encoded string (or an oher format... let me know) from parsing a mail and I can not change it. How can I decode it? This JSON response is invalid as @ThiefMaster mentioned, because JSON doesn't support duplicated keys . You should contact the service you're trying to request this response from. In case you have a valid
{"": "attachment-2","": "attachment-1"} 我得到这个JSON编码的字符串（或其他格式...让我知道）解析一个邮件，我不能改变它。 我怎样才能解码它？ 这个JSON响应无效，因为@ThiefMaster提到，因为JSON不支持duplicated keys 。 您应该联系您尝试请求此响应的服务。 如果你有一个有效的JSON响应，你可以使用返回一个object或array的json_decode函数来解码它（取决于第二个参数）。 例如：（对象） $json_string = '{"ke
This question already has an answer here: Does JSON syntax allow duplicate keys in an object? 11 answers What you've given here is not JSON, and you won't be able to create an array in PHP that has duplicate keys. While it is valid for duplicate keys to exist on an object's properties in JSON, it is discouraged as most parsers (including json_decode ) will not give you access to
这个问题在这里已经有了答案： JSON语法是否允许在对象中使用重复键？ 11个答案 你在这里给出的不是JSON，你将无法在PHP中创建具有重复键的数组。 虽然重复键在JSON中的对象属性上存在是有效的，但由于大多数解析器（包括json_decode ）不会让您访问所有这些键，因此不鼓励它。 然而，流解析器通常会让你得到这些解析器中的每一个。 使用我写的一个例子， pcrov/JsonReader ： use pcrovJsonReaderJsonReader; $json
The last week I read a lot articles about password hashing and Blowfish seems to be (one of) the best hashing algorithm right now - but that's not the topic of this question! The 72 character limit Blowfish only consider the first 72 characters in the entered password: <?php $password = "Wow. This is a super secret and super, super long password. Let's add some special ch4r4ct3rs a#d
上周我读了很多关于密码散列的文章，Blowfish似乎是（现在）最好的散列算法之一 - 但这不是这个问题的主题！ 72个字符限制 河豚只考虑输入密码中的前72个字符： <?php $password = "Wow. This is a super secret and super, super long password. Let's add some special ch4r4ct3rs a#d everything is fine :)"; $hash = password_hash($password, PASSWORD_BCRYPT); var_dump($password); $input = substr($password,
What's the best way to determine the first key in a possibly associative array? My first thought it to just foreach the array and then immediately breaking it, like this: foreach ($an_array as $key => $val) break; Thus having $key contain the first key, but this seems inefficient. Does anyone have a better solution? You can use reset and key : reset($array); $first_key = key($array)
确定可能的关联数组中的第一个键的最好方法是什么？ 我首先想到的仅仅是对数组进行foreach，然后立即将其分解，如下所示： foreach ($an_array as $key => $val) break; 因此让$ key包含第一个键，但这看起来效率低下。 有没有人有更好的解决方案？ 您可以使用reset和key ： reset($array); $first_key = key($array); 它基本上和你最初的代码一样，但是开销少一点，而且更明显的是发生了什么。 只需记住调用reset
I have two dates of the form: Start Date: 2007-03-24 End Date: 2009-06-26 Now I need to find the difference between these two in the following form: 2 years, 3 months and 2 days How can I do this in PHP? For PHP < 5.3 otherwise see jurka's answer below You can use strtotime() to convert two dates to unix time and then calculate the number of seconds between them. From this it'
我有两种形式的日期： Start Date: 2007-03-24 End Date: 2009-06-26 现在我需要通过以下形式找出这两者之间的区别： 2 years, 3 months and 2 days 我怎样才能在PHP中做到这一点？ 对于PHP <5.3，否则请参阅下面的jurka的答案 您可以使用strtotime（）将两个日期转换为unix时间，然后计算它们之间的秒数。 由此可以很容易计算出不同的时间段。 $date1 = "2007-03-24"; $date2 = "2009-06-26"; $diff = abs(strtot
I'm having serious issues understanding PHP classes from a book. They seem very difficult. What is their purpose and how do they work? In a nutshell , a Class is a blueprint for an object. And an object encapsulates conceptually related State and Responsibility of something in your Application and usually offers an programming interface with which to interact with these. This fosters co
我从一本书中了解PHP类的严重问题。 他们看起来非常困难。 他们的目的是什么？他们是如何工作的？ 简而言之 ，一个类是一个对象的蓝图。 一个对象在概念上封装了你的应用程序中相关的状态和责任，并且通常提供一个编程接口来与这些接口进行交互。 这促进了代码重用并提高了可维护性。 想象一下锁定： namespace MyExample; class Lock { private $isLocked = false; public function unlock() { $