So i want my output to be something like this: N = 3 userinput1 | userinput2 | userinput3 userinput4 | userinput5 | userinput6 userinput7 | userinput8 | userinput9 but the problem is after i insert my userinput1 and press enter it goes one space below and become like this 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | i tried to change sc.nextInt(); to sc.nex
所以我想我的输出是这样的： N = 3 userinput1 | userinput2 | userinput3 userinput4 | userinput5 | userinput6 userinput7 | userinput8 | userinput9 但问题是我插入我的userinput1并按下输入它下面的一个空间，并成为这样 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 我试图改变sc.nextInt（）; sc.nextLine（）; 但它不工作，即使我使用parseInt .. public static void
I have a code that searches for words in a text file, but the scanner that runs it is located in the public static void main(String[] args) for the class. I need to be able to move the scanner into a string, so that rather than inputting the word that I want to search for in the code manually as a word in quotes, I can find it by referencing the string in another class's main method, with a
我有一个代码在文本文件中搜索单词，但运行它的扫描器位于该类的public static void main（String [] args）中。 我需要能够将扫描器移动到一个字符串中，这样，我就可以通过引用另一个类的主要方法中的字符串来找到它，而不是在代码中手动输入要在代码中搜索的单词，用一个构造函数接受文字。 但是，当我尝试将扫描器移出主体并进入新的公共字符串时，我必须更改System.out.println（arr [0]）以返回arr [0]，并且程序将不会
If I close one scanner object and make a new one and try to read some more input, I'm getting the NoSuchElementException exception. My code works fine but it gives me a warning if I don't close the scanner. However, if I close it to get rid of the warning, I also close System.in ... How do I avoid this? Also, are there any consequences of not closing the scanner? EDIT: Here's m
如果我关闭一个扫描器对象并创建一个新对象并尝试读取更多输入， NoSuchElementException收到NoSuchElementException异常。 我的代码工作正常，但如果我不关闭扫描仪，它会给我一个警告。 但是，如果我关闭它来摆脱警告，我也关闭System.in ...我如何避免这种情况？ 另外，是否有没有关闭扫描仪的后果？ 编辑：这是我的代码： 这是NameAddressExists（）方法： public void NameAddressExists() { System.out.print
I have a class that creates multiple integer objects onto a linked list as shown below: public class Shares<E> implements Queue<E> { protected LinkedList<E> L; public Shares() { L = new LinkedList<E>(); } public boolean add(E price) { System.out.println("How many of these shares would you like?"); Scanner scanInt; scanInt = new Scanner(System.in); I
我有一个类创建多个整数对象到链表上，如下所示： public class Shares<E> implements Queue<E> { protected LinkedList<E> L; public Shares() { L = new LinkedList<E>(); } public boolean add(E price) { System.out.println("How many of these shares would you like?"); Scanner scanInt; scanInt = new Scanner(System.in); Integer noShares = scanInt.nextInt();
trying to run the program below but am getting an error when using the switch method import java.util.Scanner; /** * * @author kern public class loans { public static void main(String[] args) { Scanner input = new Scanner(System.in); //variabled decleared double rate, payment,principal,interest,n; int length; String period; //input System.out.print("Enter the amoun
试图运行下面的程序，但使用开关方法时出现错误 import java.util.Scanner; / ** * * @作者kern公共类贷款{ public static void main(String[] args) { 扫描仪输入=新扫描仪（System.in）; //variabled decleared double rate, payment,principal,interest,n; int length; String period; //input System.out.print("Enter the amount of money borrowed: $"); principal = input.nextDouble
I just installed Ubuntu 8.04 and I'm taking a course in Java so I figured why not install a IDE while I am installing it. So I pick my IDE of choice, Eclipse, and I make a very simple program, Hello World, to make sure everything is running smoothly. When I go to use Scanner for user input I get a very odd error: My code: import java.util.Scanner; class test { public static void mai
我刚刚安装了Ubuntu 8.04，并且正在学习Java课程，所以我想知道为什么不在我安装时安装IDE。 所以我选择我选择的IDE，Eclipse，并且我制作了一个非常简单的程序Hello World，以确保一切运行顺利。 当我使用Scanner进行用户输入时，我得到一个非常奇怪的错误： 我的代码： import java.util.Scanner; class test { public static void main (String [] args) { Scanner sc = new Scanner(System.in); Sy
The following code is showing an error. I am very new to coding. This thing is messing with my head. What can I do? I have tried everything I know but nothing has worked out so far. What is the best and most efficient way to code such programs? Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Scanner.java:862) at java.util.Scanner.n
以下代码显示错误。 我对编码非常陌生。 这东西正在弄乱我的头。 我能做什么？ 我已经尝试了我所知道的一切，但到目前为止没有任何结果。 什么是最好和最有效的方式来编写这样的程序？ 线程“主”中的异常 java.util.NoSuchElementException在 java.util.Scanner.throwFor（Scanner.java:862）at java.util.Scanner.next（Scanner.java:1371）at Codechef.main（Main.java:27） 以下代码是在编辑之后。 但它仍
I have used Scanner for all my programming needs, but for some reason, I'm unable to get through this error: Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Scanner.java:862) at java.util.Scanner.next(Scanner.java:1485) at java.util.Scanner.nextInt(Scanner.java:2117) at java.util.Scanner.nextInt(Scanner.java:2076) at Main.main(Main.java:9)
我已经使用扫描仪来满足我所有的编程需求，但出于某种原因，我无法解决这个错误： java.util.Scanner.nextInt（java.util.Scanner.nextInt（））中java.iotil.Scanner.next（Scanner.java:1485）上的（Scanner.java:862） Scanner.java:2117）在Main.main（Main.java:9）处的java.util.Scanner.nextInt（Scanner.java:2076） 在以下代码中： import java.util.*; import java.lang.*; import java.io.*; class Main { pu
I have a Scanner linked to System.in . Now, after using the Scanner , I should close it, as it is bad coding practice to leave it open. But, if I close the Scanner , I will also be closing System.in ! Can anyone tell me how I can close the Scanner without closing System.in (if there is any way). One option is to wrap your System.in stream in a CloseShieldInputStream that prevents it from bei
我有一个Scanner链接到System.in 。 现在，在使用Scanner ，我应该关闭它，因为打开它是不好的编码习惯。 但是，如果我关闭Scanner ，我也将关闭System.in ！ 任何人都可以告诉我如何关闭Scanner而不关闭System.in （如果有任何方法的话）。 一种选择是将System.in流封装到CloseShieldInputStream ，以防止它被关闭。 然后，您的阅读器将使用CloseShieldInputStream而不是原始System.in流。 以下是该类的API：http://com
Can anybody tell me what is wrong with my code as shown below? The first case works perfectly fine but the second and third case throws an exception : Does this have something to do with the while loops at the start of case 2 and 3? public static void main(String[] args) { Scanner scan = new Scanner(System.in); int option = scan.nextInt(); switch (option) { case 1: int l
有人可以告诉我我的代码有什么问题，如下所示？ 第一种情况非常好，但第二种和第三种情况引发异常： 这与情况2和3开始时的while循环有什么关系？ public static void main(String[] args) { Scanner scan = new Scanner(System.in); int option = scan.nextInt(); switch (option) { case 1: int line = scan.nextInt(); for (int i = 0; i < line; i++){ Str