Change private static final field using Java reflection

I have a class with a private static final field that, unfortunately, I need to change at run-time. Using reflection I get this error: java.lang.IllegalAccessException: Can not set static final boolean field Is there any way to change the value? Field hack = WarpTransform2D.class.getDeclaredField("USE_HACK"); hack.setAccessible(true); hack.set(null, true); Assuming no SecurityManager is pre

使用Java反射更改私有静态最终字段

我有一个private static final字段的类,不幸的是,我需要在运行时更改。 使用反射我得到这个错误: java.lang.IllegalAccessException: Can not set static final boolean field 有什么方法可以改变价值吗? Field hack = WarpTransform2D.class.getDeclaredField("USE_HACK"); hack.setAccessible(true); hack.set(null, true); 假设没有SecurityManager阻止你这样做,你可以使用setAccessible来避开private并重置修饰符

Spark Streaming historical state

I am building real time processing for detecting fraud ATM card transaction. in order to efficiently detect fraud, logic requires to have last transaction date by card, sum of transaction amount by day (or last 24 Hrs.) One of usecase is if card transaction outside native country for more than a 30 days of last transaction in that country then send alert as possible fraud So tried to look at

Spark Streaming的历史状态

我正在构建用于检测欺诈ATM卡交易的实时处理。 为了有效地检测欺诈行为,逻辑需要有卡的最后交易日期,白天(或过去24小时)的交易金额总和。 其中一个用例是,如果在该国境内超过30天的最后交易之后在本国以外的卡交易,则发送可能的欺诈警报 所以试图将Spark视为一种解决方案。 为了实现这一点(可能我对功能编程缺少想法)下面是我的psudo代码 stream=ssc.receiverStream() //input receiver s1=stream.mapToPair() //

Can I catch multiple Java exceptions in the same catch clause?

In Java, I want to do something like this: try { ... } catch (IllegalArgumentException, SecurityException, IllegalAccessException, NoSuchFieldException e) { someCode(); } ...instead of: try { ... } catch (IllegalArgumentException e) { someCode(); } catch (SecurityException e) { someCode(); } catch (IllegalAccessException e) { someCode(); } catch (NoSuch

我可以在同一个catch子句中捕获多个Java异常吗?

在Java中,我想要做这样的事情: try { ... } catch (IllegalArgumentException, SecurityException, IllegalAccessException, NoSuchFieldException e) { someCode(); } ...代替: try { ... } catch (IllegalArgumentException e) { someCode(); } catch (SecurityException e) { someCode(); } catch (IllegalAccessException e) { someCode(); } catch (NoSuchFieldException e)

Removing whitespace from strings in Java

I have a string like this: mysz = "name=john age=13 year=2001"; I want to remove the whitespaces in the string. I tried trim() but this removes only whitespaces before and after the whole string. I also tried replaceAll("\W", "") but then the = also gets removed. How can I achieve a string with: mysz2 = "name=johnage=13year=2001" st.replaceAll("\s+","&qu

在Java中删除字符串中的空格

我有这样一个字符串: mysz = "name=john age=13 year=2001"; 我想删除字符串中的空格。 我试过trim()但是这样只删除整个字符串前后的空格。 我也试过replaceAll("\W", "")但是=也被删除。 我如何实现一个字符串: mysz2 = "name=johnage=13year=2001" st.replaceAll("\s+","")将删除所有空格和不可见字符(例如,标签, n )。 st.replaceAll("\s+","")

Why in Java 8 split sometimes removes empty strings at start of result array?

Before Java 8 when we split on empty string like String[] tokens = "abc".split(""); split mechanism would split in places marked with | |a|b|c| because empty space "" exists before and after each character. So as result it would generate at first this array ["", "a", "b", "c", ""] and later will remove trailing empty strings (because we didn't explicitly provide negative valu

为什么在Java 8中split有时会在结果数组开始时删除空字符串?

在Java 8之前,当我们像空字符串一样分割时 String[] tokens = "abc".split(""); 拆分机制会在标有|地方拆分 |a|b|c| 因为在每个字符之前和之后存在空格"" 。 因此,它最初会产生这个数组 ["", "a", "b", "c", ""] 之后会删除尾随的空字符串(因为我们没有明确提供负值来limit参数),所以最终会返回 ["", "a", "b", "c"] 在Java 8中,拆分机制似乎已经发生了变化。 现在当我们使用 "abc".split("") 我们

@ControllerAdvice exception handling together with @ResponseStatus

I have @ControllerAdvice class, which handles a set of exceptions. Than we have some other exceptions, which are annotated with @ResponseStatus annotation. To combine both approaches, we use technique described in blog post: http://spring.io/blog/2013/11/01/exception-handling-in-spring-mvc, namely in the ControllerAdvice we handle generic Exception in the following way: @ExceptionHandler(v

@ControllerAdvice异常处理与@ResponseStatus一起

我有@ControllerAdvice类,它处理一组异常。 比我们还有其他一些例外,它们用@ResponseStatus注解来标注。 为了结合这两种方法,我们使用博客文章中描述的技术:http://spring.io/blog/2013/11/01/exception-handling-in-spring-mvc,即在ControllerAdvice我们处理下面的通用Exception办法: @ExceptionHandler(value = Exception.class) public ModelAndView defaultErrorHandler(HttpServletRequest req, Exception

How to convert component of String[] or Object[] to other type

This question already has an answer here: How do I convert a String to an int in Java? 30 answers Java - Convert integer to string [duplicate] 7 answers You can use Integer.parseInt() without an issue. int i = input[0] // i is an int while input[0] is a String Now int i=Integer.parseInt(input[0]) will convert String to int Integer.parseInt()

如何将String []或Object []的组件转换为其他类型

这个问题在这里已经有了答案: 如何在Java中将字符串转换为int? 30个答案 Java - 将整数转换为字符串[重复] 7个答案 你可以使用Integer.parseInt()而没有问题。 int i = input[0] // i is an int while input[0] is a String 现在 int i=Integer.parseInt(input[0]) 将String转换为int 的Integer.parseInt()

Getting an information about type of input ( main args )

This question already has an answer here: How do I convert a String to an int in Java? 30 answers 最简单的方法是使用parseInt进行检查。 public static void main(String[] args) throws InterruptedException { try { Integer.parseInt(args[0]); } catch(NumberFormatException e) { System.out.println("It is not a number."); } } args[] takes in all the arguments s

获取关于输入类型的信息(主要参数)

这个问题在这里已经有了答案: 如何在Java中将字符串转换为int? 30个答案 最简单的方法是使用parseInt进行检查。 public static void main(String[] args) throws InterruptedException { try { Integer.parseInt(args[0]); } catch(NumberFormatException e) { System.out.println("It is not a number."); } } args[]接受所有提供给main方法的参数,所以args[0]虽然是一个Strin

Java : convert a String to Int (Unknown Source)

This question already has an answer here: How do I convert a String to an int in Java? 30 answers Integer.parseInt(“9999999990”); [duplicate] 2 answers 98597598684 is greater than Integer.MAX_VALUE . Use long id = Long.parseLong(filename1.substring(0, filename1.length() - 4)); 你甚至可以尝试new BigInteger("98597598684")

Java:将字符串转换为Int(未知源)

这个问题在这里已经有了答案: 如何在Java中将字符串转换为int? 30个答案 的Integer.parseInt(“9999999990”); [重复] 2个答案 98597598684大于Integer.MAX_VALUE 。 使用 long id = Long.parseLong(filename1.substring(0, filename1.length() - 4)); 你甚至可以尝试new BigInteger("98597598684")

how to convert string to int in Java

This question already has an answer here: How do I convert a String to an int in Java? 30 answers How do I convert from int to String? 19 answers Ask following questions to your self first. What your method want as parameter? Why both are Incompatible? What String cipherText = cc.encrypt(plainText,key); mean? key is String or int ? Use methods like Integer.parseInt(String value

如何在Java中将字符串转换为int

这个问题在这里已经有了答案: 如何在Java中将字符串转换为int? 30个答案 如何从int转换为String? 19个答案 首先询问以下问题。 你的方法需要什么参数? 为什么两者不兼容? 什么String cipherText = cc.encrypt(plainText,key); 意思? 键是String还是int ? 使用像Integer.parseInt(String value)或Integer.valueOf(String value)进行转换。 看来你需要将一个String转换为int ,而不是一个int为String